Time:logs=time:logs
time/logs=time/logs
4hours:6logs=18hours:xlogs
4hours/6logs=18hours/xlogs
4/6=18/x
6/4=18/x
x=27
pick B,C,E
6*14=84
the answer is 84cm²
Answer:
149.8 feet
Step-by-step explanation:
θ = Angle of elevation = 33°
The length of string Jaden lets out = Hypotenuse = 275 feet.
How high above the ground that the kite is flying = Opposite Side.
We are solving this question using the Trigonometric function of Sine
Sin θ = Opposite Side/Hypotenuse
Sin 33 = Opposite/275 feet
Cross Multiply
Sin 33 × 275 feet = Opposite
Opposite side(Height ) = 149.77573463 feet
Approximately to the nearest tenth = 149.8 feet
Complete Question
In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Answer:
16.5°
Step-by-step explanation:
In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
We solve using Sine rule formula
a/sin A = b/sin B
We are solving for angle W
∠V=136°
Hence:
22 /sin 136 = 9 /sin W
Cross Multiply
22 × sin W = sin 136 × 9
sin W = sin 136 × 9/22
W = arc sin [sin 136 × 9/2.2]
W = 16.50975°
W = 16.5°
