Sabemos que la cuerda mas pequeña mide 96 metros, asi que debemos descomponer 96 en sus factores primos para encontrar los divisore de 96 y comparar si esos divisor tambien dividen a 120. En la imagen adjunta está la descomposición de 96 en sus factores primos.
Ahora que sabemos que
, podemos hallar que los divisores de 96 son: 96,
,
,
,
, 2 y 3. De todos esos los mas grandes son 96, 48 y 24. Asi que vamos encontrar por cual de ellos es divisible 120:
el resultado de la division no es un entero, no nos sirve.
el resultado de la division no es un entero, no nos sirve.
este es nuestro número!
Ahora sabemos que Andrés debe cortar ambas cuerdas en trozos de 24 metros para que los trozos sean iguales y tengan el maximo largo posible. Ahora para hallar cuantos trozos de cuerda serían vamos a dividir cada una de las cuerdas por el largo de uno de los trozos:
Para la primera cuerda:
Para la segunda cuerda:
Ahora solo tenemos que sumar los trozos para hallar el total de trozos:
Podemos concluir que Andrés debe cortar ambas cuerdas en
9 trozos de 24 metros para que los trozos sean iguales y tengan el maximo largo posible.
We can solve this quadratic equation using factorisation method as follows
:x2−5x−36=0
x2+4x−9x−36=0
x(x+4)−9(x+4)=0
(x+4)×(x−9)=0
x+4=0orx−9=0
x=−4orx=9
Answer:
I'm sorry I don't know the ratio but the whole number of students is 164 and dance students is 43 i hope this helps if not im sorry i tried to help
Step-by-step explanation:
Answer:
123
Step-by-step explanation:
if the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadth
The answers are x = 6 and z = 83
z can be found through the fact that the straight line created by it and the 97 degree angle would add to 180 degrees. After subtracting 97 from the 180 total, the answer of 83 would be apparent.
As for the x, the opposite angles will equal each other. Therefore:
11x + 31 = 97 ----> Subtract 31 from both sides
11x = 66 ---> Divide both sides by 11
x = 6