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weeeeeb [17]
3 years ago
12

What is the greatest possible number of 27 and 36

Mathematics
1 answer:
Licemer1 [7]3 years ago
3 0
I Believe Its 9
9 * 3 = 27
9 * 4 = 36
Or
27 / 9 = 3
36 / 9 = 4
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Solve the problem. The formula d = rt gives the distance traveled in time t at rate r. If a bicyclist rides for 2.3 hours and tr
Contact [7]

Answer:

17.83

Step-by-step explanation:

d = r*t

d = 41 miles

t = 2.3 hours

r = ??

d = rt            Substitute

41 = r * 2.3   Divide by 2.3

41 / 2.3 = r   Switch sides

r = 41/2.3

r = 17.83 mph  Answer


4 0
3 years ago
Of the $77.84 direct-deposited from Problem 3, you have 50% placed into a savings account. How much is deposited in the saving a
In-s [12.5K]

Answer:

38.92 dollars

Step-by-step explanation:

3 0
3 years ago
A publishing industry report predicts that magazine subscriptions will drop by 5% each year. If this prediction is correct, then
Rzqust [24]

Answer:

The no. of subscribers of the magazine after 5 years is = 55713

Step-by-step explanation:

Given data

Total subscribers (N) = 72000

Drop in subscriptions in each year (R) = 5%

No. of subscribers of the magazine in 5 years is given by

N_1 = N (\frac{R}{100} )^{T}

N_1 = 72000 (0.95)^{5}

N_1 = 55713

Thus the no. of subscribers of the magazine after 5 years is = 55713

4 0
3 years ago
Match the function in the left column with its period in the right column.
kiruha [24]

The results for the matching between function and its period are:

  • Option 1 - Letter D
  • Option 2 - Letter A
  • Option 3 - Letter C
  • Option 4 - Letter B

<h3>What is a Period of a Function?</h3>

If a given function presents repetitions, you can define the period as the smallest part of this repetition. As an example of periodic functions, you have: sin(x) and cos(x).

\mathrm{Period\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}

The period of sin(x) and cos(x) is 2π.

For solving this question, you should analyze each option to find its period.

1) Option 1

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi }{\frac{1}{2} }=4\pi

Thus, the option 1 matches with the letter D.

2) Option 2

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{4} =\frac{\pi }{2}

Thus, the option 2 matches with the letter A.

3) Option 3

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{2} =\pi

Thus, the option 3 matches with the letter C.

4) Option 4

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{8} =\frac{\pi }{4}

Thus, the option 4 matches with the letter B.

Read more about the period of a trigonometric function here:

brainly.com/question/9718162

#SPJ1

6 0
2 years ago
Subscribe to my yt please and I will surely give you the brainliest.
lilavasa [31]

Answer:

say no more , link it down below

3 0
3 years ago
Read 2 more answers
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