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Andrej [43]
3 years ago
7

Simplify 36n^7p^5/9n^4p

Mathematics
1 answer:
Galina-37 [17]3 years ago
7 0
Answer : 4n^3p^4 {^—^}
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A tree DOUBLES in height each year until it reached its maximum height over the course of 10 years. How many years did it take f
RideAnS [48]

Answer:

9 years

the tree doubles in height

we can make a model

1 x 2 = 2

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 x 2 = 128

128 x 2 = 256

256 x 2 = 512

512 x 2 = 1024

Let's say 1024 is the maximum height

half the maximum height is 1024 x 0.5 = 512 so it will take 9 years because it reached 512 on the 9th year

Step-by-step explanation:

8 0
4 years ago
Pls help for brainliest
Minchanka [31]

。☆✼★ ━━━━━━━━━━━━━━  ☾

πr^2 = area

Half the diameter to get the radius

Substitute the values in:

area = 3.142 x (7)^2

area = 153.958 cm^2

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8 0
4 years ago
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Three squares. The first square is labeled with side length 1 inch on the vertical side and 1 inch on the horizontal side. The s
dlinn [17]

Answer:

The area is the side lengths squared or multiplied by themselves. The three squares have very different areas based on their side lengths. I disagree that a square with 13 inch side length will have area 13. It will have area 13*13=169 square inches.

Step-by-step explanation:

The area of a square is A=s*s.

1st: A = 1*1 = 1 square inches.

2nd: A=1/2*1/2 = 1/4 square inches

3rd: A =2*2 = 4 square inches.

The area of a square with 1 unit side length is still 1. But a square whose side is less than 1 has a very small area and the square whose side length is greater than 1 has a much larger area. The area of a square is the square of its side length or its side length times itself.

Knowing this, a square with side length 13 will not have area 13 but area 169.

8 0
3 years ago
Employee B got a one time $90 bonus. He got
Svetllana [295]

Answer:

$10 an hour

Step-by-step explanation:

Subtract the bonus to get the pay.

330-90=240

Divide 240 by 24 hours to get his rate of pay.

240/24=10

He gets $10 an hour.

3 0
4 years ago
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