47.5 mph- because 30+65 equals 95 and 95 divided by 2 is 47.5
Answer: ![\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{17}{3}\:\\ \:\mathrm{Decimal:}&\:x\le \:5.66666\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{17}{3}]\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ax%5Cle%20%5Cfrac%7B17%7D%7B3%7D%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ax%5Cle%20%5C%3A5.66666%5Cdots%20%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A%5Cfrac%7B17%7D%7B3%7D%5D%5Cend%7Bbmatrix%7D)
Step-by-step explanation:
The answer is was he number is being divided by 10
Answer:
disagree
Step-by-step explanation:
The interquartile range is a measure of how spread out values are in a data set.
It doesn't actually consider the values, it is found by finding the range between the Q1 / 25th percentile and the Q3 / 75th percentile --and a "range" is found by finding the difference between these two numbers (by subtracting).
So, the weather could have been something like:
79 79 79 80 81 81 83 85 96 97
79 79 79 80 81 | 81 83 85 96 97
meaning that the interquartile range is 6, but these temperatures are not low
(if you want me to explain how to find the interquartile range more thoroughly, please let me know)
Answer:
C
Step-by-step explanation:
Write the expression out
factor it
cancel out all everything that is the same and appears on both the top and the bottom
Cancel out:
(x+1)
(x)
(x)
leaves you with
3 goes into 6 '2' times so the 3 in the numerator cancels out too. The 6 in the denominator turns into a 2
This leaves you with the final answer of
