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Over [174]
3 years ago
15

Please help....What is a problem that makes sense for this question? ASAP!!

Mathematics
1 answer:
ddd [48]3 years ago
7 0

Explanation:

250 can be used as a total, with 10 being how much something subtracted multiple times takes away, and 20 being the end result. So, we could make the problem about a lot of things, but I'll go ahead and write the first one that comes to mind.

Answer:

Arata has $250 in his bank account, and plans on buying several CDs. Each one costs $10, and by the end of the trip, there is only $20 left in his account. How many CDs did Arata buy, assuming there was no tax or other additional charges?

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I need help I can’t figure it out
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Answer:

\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}

Step-by-step explanation:

\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}

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3 years ago
Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 6-inch radius A = sq. in.
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\bf \textit{area of an equilateral triangle}\\\\
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Answer:

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3 years ago
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