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4 years ago

What are the similarities and differences between these data sets in terms of their centers and their variability?

Mathematics

2 answers:

slega [8]4 years ago

8 0

Answer:

Step-by-step explanation:

The given data set A is:

16, 10, 18, 24

Arrange in ascending order, we have

10,16, 18, 24

Since, median is the mid value of the given set, therefore

$Median of set A=\frac{10+18}{2}=14$

Range of the given data set A is given as:

$Range=24-10=14$

The given data set B is:

21, 14, 16, 14, 19

Arrange in ascending order, we have

14, 14, 16, 19, 21

Since, median is the mid value of the given set, therefore

$Median of set B=16$

Range of the given data set B is given as:

$Range=21-14=7$

Median of data set A is less than data set B and the range of data set A is greater than range of the data set B.

Xelga [282]4 years ago

4 0

Because the choices concern more about the median, the median of Data set A is equal to 17. The median of Data set B is 16. Thus, the median for A is not exactly similar to the median of B.

The range of Data Set A is 8 while that of Data Set B is 7. Thus, the range of A is greater compared to B.

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3 years ago

What is the value of y?

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4 years ago

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3 years ago

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73. Suppose that you want to buy a house that costs $175,000. You can make a 10% down payment, and 1.2% of the house’s value is

Irina-Kira [14]

Answer:

total monthly payment is $973.03

Step-by-step explanation:

given data

costs = $175,000

down payment = 10%

house value paid = 1.2%

to find out

monthly payment for a 30 year i.e 360 months

solution

we consider here rate of interest for 30 year is 4.25% so monthly interst rate will be $\frac{0.0425}{12}$ = 0.00375

so We have present value Ap = 0.9 ( 175000) = $157500

and the monthly escrow payment is

monthly escrow payment = $\frac{1}{12}$ × 0.012 × 175000

monthly escrow payment = $175

so monthly payment formula is

monthly payment = $\frac{Ap*r}{1-(1+r)^{-n}}$ ..................1

here r is rate and n is time period

monthly payment = $\frac{157500*0.00375}{1-(1+0.00375)^{-360}}$

monthly payment = 798.03

so the payment to the loan is $798.03 each month

and Then the total monthly payment is = $798.03 + $175

total monthly payment is $973.03

5 0

3 years ago

We are standing on the top of a 1680 ft tall building and throw a small object upwards. At every second, we measure the distance

MAVERICK [17]

Answer:

a) The height of the small object 3 seconds after being launched is 2304 feet.

b) The small object ascends 128 feet between 5 seconds and 7 seconds.

c) The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) The object will take 21 seconds to hit the ground.

Step-by-step explanation:

The correct formula for the height of the small object is:

$h(t) = -16\cdot t^{2}+256\cdot t+1680$ (1)

Where:

$h$ - Height above the ground, measured in feet.

$t$ - Time, measured in seconds.

a) The height of the small object at given time is found by evaluating the function:

$h(3\,s)= -16\cdot (3\,s)^{2}+256\cdot (3\,s)+1680$

$h(3\,s) = 2304\,ft$

The height of the small object 3 seconds after being launched is 2304 feet.

b) First, we evaluate the function at $t = 5\,s$ and $t = 7\,s$ :

$h(5\,s)= -16\cdot (5\,s)^{2}+256\cdot (5\,s)+1680$

$h(5\,s) = 2560\,s$

$h(7\,s)= -16\cdot (7\,s)^{2}+256\cdot (7\,s)+1680$

$h(7\,s) = 2688\,s$

We notice that the small object ascends in the given interval.

$\Delta h = h(7\,s)-h(5\,s)$

$\Delta h = 128\,ft$

The small object ascends 128 feet between 5 seconds and 7 seconds.

c) If we know that $h = 2640\,ft$ , then (1) is reduced into this second-order polynomial:

$-16\cdot t^{2}+256\cdot t-960=0$ (2)

All roots of the resulting equation come from the Quadratic Formula:

$t_{1} = 10\,s$ and $t_{2}= 6\,s$

The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) If we know that $h = 0\,ft$ , then (1) is reduced into this second-order polynomial:

$-16\cdot t^{2}+256\cdot t +1680 = 0$ (3)

All roots of the resulting equation come from the Quadratic Formula:

$t_{1} = 21\,s$ and $t_{2} = -5\,s$

Just the first root offers a solution that is physically reasonable.

The object will take 21 seconds to hit the ground.

8 0

3 years ago