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Irina18 [472]
2 years ago
5

An _ is a segment that extends from the vertex of a triangle and is perpendicular to the opposite side

Mathematics
1 answer:
maksim [4K]2 years ago
6 0
Answer———-
(((Altitude)))
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Y=3x^2+3x-5. and 2x-y=3
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Given that cos (x) = 1/3, find sin (90 - x)
ddd [48]

Answer:

\sin(90^{\circ} - x)=\frac{1}{3}

Step-by-step explanation:

Given: \cos (x)=\frac{1}{3}

We have to find the value of \sin(90^{\circ} - x)

Since Given \cos (x)=\frac{1}{3}

Using trigonometric identity,

\sin(90^{\circ} - \theta)=\cos\theta

Thus, for  \sin(90^{\circ} - x) comparing , we have,

\theta=x

We get,

\sin(90^{\circ} - x)=\cos x=\frac{1}{3}

Thus, \sin(90^{\circ} - x)=\frac{1}{3}

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3 years ago
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Neko [114]

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(7,2) it’s just basic graphing
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