1.explain how you would graph the inequality y<2/3x+1 on a coordinate plane. Be very specific and describe all your steps ple
1 answer:
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Answer:
Shift "h" units to the right, "k" units up, and reflect over the x or y axis when needed.
Step-by-step explanation:
1) I want to talk about reflections first.
- Reflections across the x-axis -->
, a is the coefficient. if a is negative, then the equation should be reflected across the x-axis. This is known as a vertical reflection.
- Reflections across the y-axis -->
, b is the coefficient. If b is negative, then reflect the equation over the y-axis. There are cases where the reflection across the y-axis does not change anything. But, let's say its
... the reflection across the y-axis is different (that equation is:
)
2) Rigid transformations
- Horizontal transformations (to the left or right):
, factor out b from "bx-h" and whatever h equals is the units to the right. If h is a negative number, then you move to the left.
- Vertical transformations (up and down):
... k is just the units up... if k is negative then we move it down.
Example (check image for visual)
We transform to
, you move right 3, then reflect across the x-axis, then reflect across y-axis, then move 3 up.
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Note: In the image, the red line is the original function, the blue one is the transformed function. See if you can follow along with the verbal instructions I gave above.
