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kramer
3 years ago
14

One spinner has three equally sized sectors numbered 1, 2, and 3. A second spinner has two equally sized sectors labeled Top (T)

and Bottom (B). Each spinner is spun once.
What is the sample space of outcomes?

{1, 2, 3, T, B}{BT, 123}{B1, B2, B3, T1, T2, T3}{BT, BB, TB, 11, 12, 13, 21, 22, 23, 31, 32, 33}
Mathematics
2 answers:
maria [59]3 years ago
5 0

Answer:

{B1,B2,B3,T1,T2,T3}

Step-by-step explanation:

{B1,B2,B3,T1,T2,T3} Therefore you could get top or bottom with each number so in that case your 3rd choice is correct

SSSSS [86.1K]3 years ago
4 0
I would say, well, if there are 3 sides that are equal on spinner 1. They are equal. But, we are focusing on spinner two that has two sides. If there is only 2 equal sides then, they would have to be straight across from each other. So that is 180. 360 is full circle. take away 180 to get answer. 
360-180=180
I hope this helped. And sorry if it is not the correct answer. But that is how I would of answered it
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if you divide a positive number by 12, the answer would be less than the original number? always, sometimes, or never​
elena55 [62]

Answer:

Always

Step-by-step explanation:

The rules for positive numbers is that addition and multiplication makes numbers larger. Subtraction and division makes numbers smaller.

Since 12 is a positive number, the result of dividing a positive number by 12 will make it smaller.

8 0
4 years ago
Given: A = { -1,5,6} B = {-1,2,3,4,6,8} Find the union of sets A and B.
lukranit [14]

Step-by-step explanation:

{-1,2,3,4,5,6,8} is the answer

4 0
2 years ago
Jessica has $24 and plans to spend it all at the grocery store. She wants to purchase bags of carrots and bagels. Bags of carrot
Andrei [34K]
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6 0
4 years ago
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Find the particular solution to y ′ = 3sin(x) given the general solution is y = C − 3cos(x) and the initial condition y(π) = 1.
quester [9]
y=C-3\cos

y(\pi)=1
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So the particular solution is

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8 0
4 years ago
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Last question of the section
klasskru [66]

Answer:

SA of black base: 84 cm^2

SA of blue faces: 84 cm^2

SA of gold faces: 60.2 cm^2

SA of 1 ornament: 228.2 cm^2

SA of 100 ornaments: 22,820 cm^2

Step-by-step explanation:

SA of black base:

A = lw

A = 7(12)

A = 84 cm^2

SA of blue faces:

A = bh

(don't divide by 2 since there are 2 triangles)

A = 12(7)

A = 84 cm^2

SA of gold faces:

A = 7(8.6)

(don't divide by 2 since there are 2 triangles)

A = 60.2 cm^2

SA of 1 ornament:

Add #s in bold:

84 + 84 + 60.2 = 228.2 cm^2

SA of 100 ornaments:

Multiply SA of 1 ornament by 100:

228.2(100) = 22,820 cm^2

7 0
3 years ago
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