Answer:
csc θ =
/6
sec θ =
/7
tan θ = 6/7
Step-by-step explanation:
The first thing to do will be to compute the length of the hypotenuse using the Pythagoras theorem;
6^2 +7^2 = hypotenuse^2
hypotenuse = 
csc θ = 1/sinθ
sinθ = opposite side/hypotenuse
= 6/
csc θ =
/6
sec θ = 1/cosθ
cosθ = adjacent side/hypotenuse
sec θ = hypotenuse/adjacent side
=
/7
tan θ = Opposite side/adjacent side
= 6/7
EQUI = equals
VALent, as in value related
EQUI + VALent, same value
M = (x1 + x2 / 2 , y1 + y2 / 2 )
Essentially you take the two points that the line ends and begins on. (x1, y1) and (x2, y2) then add the x's and the y's together and divide them by two and you have two points. That's the midpoint.
Hope this is helpful and I'm onto the right topic!
The inside perimeter would be the perimeter of the garden: 17 + 17 + 20 + 20 = 74 feet.
The outside dimensions would be 6 feet longer on each side ( 3 feet wide on both sides for the sidewalk)
Outside perimeter: 23 + 23 + 26 + 26 = 98 feet.
Total = 74 + 98 = 172 feet.