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3 years ago

What is the following product? (x square root 7 - 3 square root 8) (x square root 7 - 3 square root 8)

Mathematics

2 answers:

bogdanovich [222]3 years ago

8 0

Answer:

7x^2 -6x√56 + 72

Step-by-step explanation:

(x√7 - 3√8)(x√7 - 3√8) ➡ (x√7 - 3√8)^

x^2 × 7 - 3x√56 - 3x√56 + 9×8 ➡ 7x^2 -6x√56 + 72

Semmy [17]3 years ago

3 0

Answer:

7 x² - 6 x √56 +72

Step-by-step explanation:

Let's consider the following equation.

(x√7 - 3√8).(x√7 - 3√8)

This is equal to a squared binomial.

(x√7 - 3√8)²

This is equal to the square of the first term, minus the double of the product of the first by the second plus the square of the second term.

(x√7)² - 2 × x√7 × 3√8 + (3√8)²

7 x² - 6 x × √(7.8) + 9 . (√8)²

7 x² - 6 x √56 +72

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Use the formula A=bhto find the area of the parallelogram. 2.1 m 6.3 m

Feliz [49]

Answer:

A = 13.23 m²

Step-by-step explanation:

A = bh

Where,

A = area of the parallelogram

b = base of the parallelogram

h = height of the parallelogram

From the question, assume

b = 2.1 m

h = 6.3 m

A = bh

= 2.1 m × 6.3 m

= 13.23 m²

A = 13.23 m²

7 0

3 years ago

Joshua Bennett purchased a television for $245.95 with 40.25% down. He will make 6 payments of $25.83 each. What is the total am

brilliants [131]

(245.95×0.4025)+(6×25.83)=253.97

253.97-245.95=8.02

4 0

3 years ago

Read 2 more answers

The receipt shows the prices of goods that Robert bought at the store.

Vladimir79 [104]

Answer:

Step-by-step explanation : by subtracting the 8 by 4

5 0

3 years ago

Need help plz.......

Maru [420]

Answer:

oh I see. that's an interesting question but the problem is I hate maths

8 0

3 years ago

. Consumer Awareness In 1986, the average cost of a new midsize four-door sedan was $9000. In 1991, the average cost was $12,000

eduard

Answer-

$\boxed{\boxed{y=9000(1.0592)^x}}$

And cost of a car in the year 2000 will be $20134.18

Solution-

Let's assume,

x = number of years after 1986

y = average cost of sedan in dollar

The exponential model that will model the scenario will be in the form of,

$y=ab^x$

where a and b are constants

As given that, in 1986 average cost of sedan was $9000 and in 1991 average cost of sedan was $12000

So, the points (0, 9000) and (5, 12000) will satisfy or lie on the exponential curve.

Putting (0, 9000) in the equation,

$\Rightarrow 9000=ab^0$

$\Rightarrow a\times 1=9000$

$\Rightarrow a=9000$

Now, the equation becomes $y=9000b^x$

Putting (5, 12000) in this equation,

$\Rightarrow 12000=9000b^5$

$\Rightarrow b^5=\dfrac{12000}{9000}$

$\Rightarrow b=\sqrt[5]{\dfrac{4}{3}}$

$\Rightarrow b=1.0592$

Putting the values,

$y=9000(1.0592)^x$

As we have to calculate the cost of sedan in 2000, so putting x=14(as 2000-1986=14),

$y=9000(1.0592)^{14}=20134.18$

Therefore, cost of a car in the year 2000 will be $20134.18

8 0

3 years ago