Answer:
Resource management is the system level transmission cellular networks and wireless communication.
Explanation:
Wireless communication is the process to continue to the address for faster response time,to the resource management.
Transmission is the provided by that more utilization and wireless resources available,and to discovered data.
Wireless communication system to demand the larger bandwidth and transmission using development to the system.
Wireless communication resources management the larger bandwidth and reliable transmission consumed all the system layer.
Resource management techniques tool are used in a preliminary concepts or mathematical tools,and average limited power battery.
Resource management are they necessary mathematical and fundamental tools are used in wireless communication.
Wireless communication in the provide that wireless industry in a wireless communication.
Here is a somewhat cryptic solution that works:
#include <algorithm>
#include <cstdlib>
using namespace std;
void q(char c, int count)
{
for (int i = 0; i < count; i++) {
putchar(c);
}
}
void p(int b1, int plusses)
{
q(' ', b1);
q('+', plusses);
}
int main()
{
for (int i = -3; i <= 3; i++)
{
int pl = min(6, (3 - abs(i)) * 2 + 1);
p(6-pl, pl);
i == 0 ? p(0, 6) : p(6, 0);
p(0, pl);
putchar('\n');
}
getchar();
}
YOU COULD POTTENTIALLY HAVE TO WIPE ALL CURRENT FILES CLEAN OR U MAY HAVE TO PAY FOR CERTAIN PROGRAMS
Answer:
see below
Explanation:
The program of interest is the function "findMode[x, n]" in the attached. It is written the Wolfram Language of Mathematica.
The basic idea is that the data in the array is sorted. The sorted array is partitioned into sets of identical elements, and the number in each of those sets is counted. The maximum of those counts is the mode. The location of the maximum count corresponds to the location of the set having that count. We use that location information to pull out the mode value(s).
If there is more than one mode, all are reported.
__
An example data array is provided, along with the program output.
Answer:
3
Explanation:
= 1 + (int) (4*(63 - 51)/(71-51)))
= 1 + (int) (4*12/20)
= 1 + (int) (48/20)
= 1 + (int)2.4
= 1 + 2
= 3
