1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Crank
4 years ago
11

Steve has 12 biscuits in a tin.

Mathematics
1 answer:
AfilCa [17]4 years ago
4 0

Answer:

The asnwwer is

Have a Great Day

You might be interested in
4,362,784 rounded to the greatest place value is?
tiny-mole [99]

Answer: 4,000,000

Step-by-step explanation:

4 is the greatest in place values. 3 is lower than 5 so 4 stays the same.

5 0
4 years ago
Read 2 more answers
How do I solve this problem? It’s been awhile since I’ve done math
Helga [31]

Answer:

y = C/h - 2

Step-by-step explanation:

Equation

C = (2 + y)*h

Solution

C = (2 + y)*h                          Divide by h

C/h = (2 + y)*h/h

C/h = 2 + y                            Subtract 2 from both sides

C/h-2 = 2-2+ y                      Combine

C/h - 2 = y

3 0
2 years ago
Which statement best describes the relationship between ABC and EDC?
sattari [20]
The first one
mecayse m3 is equal to 
8 0
3 years ago
Could -free, automatic faucets actually be housing more bacteris than the old fashioned, manual kind The concern is that decreas
Volgvan

Answer:

Not enough evidence to reject Null hypothesis

Step-by-step explanation:

Solution:-

- A comparative study for bacterial growth in manual and electronic faucets is made.

- It is observed that there is a higher growth in electronic faucets due to slower flow rates, i.e electronic faucets are not thoroughly flushed; hence, giving more resident time for the scaled bacteria to grow.

- It is known that 15% of cultures from older faucets were tested positive for the Legionella bacteria.

- A study at John Hopkins was conducted on a sample n = 20 electronic faucets with the probability of bacteria growing in a faucet is 0.15.

- We will conduct a hypothesis for at-least half proportion of electronic faucets have cultured bacteria.

- State the hypothesis for the proportion of electronic faucets culturing Legionella bacteria:

        Null Hypothesis:  P = 0.15

        Alternate hypothesis: P > 0.15    

- To determine the test statistics for the study conducted at John hopkins. We had a sample size of n = 20, and the probability for a bacteria to grow in a faucet is 0.15.

- Denote random variable, X: The number of electronic faucets culturing Legionella bacteria.

- Since, the probability for a bacteria to grow in a faucet is independent for each new faucet. We will assume the RV " X " to follow binomial distribution with probability of success 0.15:

                      X ~ Bin ( 20 , 0.15 )                  

- We are to determine that at-least half of the sample is subjected to the said bacteria. This is the probability of P ( X ≥ 10 ).

- The pmf for a binomially distributed random variable X is given below:

                     P ( X = r ) = n_C__r * ( p(success) )^r * ( p (fail) )^(^n^-^r^)

Where,

            p ( success ) = 0.15

            p ( fail ) = 1 - p ( success ) = 1 - 0.15 = 0.85

- Use the pmf to determine the required test statistics:

P ( X \geq 10 ) = 1 - P ( X \leq  9 )\\\\P ( X \geq 10 ) = 1 - [ (0.85)^2^0 + 20*(0.15)*(0.85)^1^9 + 20_C_2 (0.15)^2*(0.85)^1^8 +\\\\ 20_C_3 (0.15)^3*(0.85)^1^7 + 20_C_4 (0.15)^4*(0.85)^1^6 + 20_C_5 (0.15)^5*(0.85)^1^5+\\\\ 20_C_6 (0.15)^6*(0.85)^1^4 + 20_C_7 (0.15)^7*(0.85)^1^3 + 20_C_8 (0.15)^8*(0.85)^1^2 + \\\\ 20_C_9 (0.15)^9*(0.85)^1^1\\\\\\P ( X \geq 10 ) = 1 - [  0.03875 + 0.13679 + 0.22933 + 0.24282 + 0.18212 + 0.10284 + \\\\ 0.04537 + 0.01601 + 0.00459 + 0.00108 ]\\\\

P ( X \geq 10 ) = 1 - [ 0.997 ] = 0.003

- The probability that 10 or more electronic faucets is found to have Legionella bacteria growing is 0.003              

- The test proportion of 10 and more electronic faucets have culturing bacteria is p = 0.003.

- Assuming normality of the population, the Z-statistics would be:

                  Z-test = \frac{ (p - P) \sqrt{n} }{\sqrt{P*(1 - P )} } \\\\Z-test = \frac{ (0.003 - 0.15) \sqrt{20} }{\sqrt{0.15*(0.85)} } \\\\Z-test = -1.84109

- If we were to test the claim to 90% level of confidence:

                  significance level (α) = 1 - CI = 1 - 0.9 = 0.1

- The rejection region Z-critical is defined by a right-tail:

                 Z-critical \geq Z_\alpha \geq Z_0_._2\\\\Z-critical \geq 1.28    

- Compare the test statistics with the rejection criteria defined by the Z-critical:

                Z-test < Z-critical

                -1.84 < 1.28

Conclusion:

There is not enough evidence that the probability of Legionella bacteria growing in electronic faucets is greater than 15%.

3 0
4 years ago
I GIVEEE BRAINLILSTT
skelet666 [1.2K]
T(-5,-10)
U(10,-10)
V(-5,5)
6 0
3 years ago
Read 2 more answers
Other questions:
  • Suppose that a box contains 6 cameras and that 4 of them are defective. a sample of 2 cameras is selected at random. define the
    5·1 answer
  • The sum of two numbers is -12. One of the numbers is 4. What is the other number?
    7·1 answer
  • Factor 4y^2 - 4y - 20
    12·1 answer
  • A salesperson is. On 50/50 split with an agency and sells a 300 acare farm at 1200 per acre. The commission schedule calls for %
    13·1 answer
  • From least to greatest -5 3/4, -7.2, 9, 3 1/8
    12·2 answers
  • An automobile purchased for ​$39,000 is worth ​$2400 after 6 years. Assuming that the​ car's value depreciated steadily from yea
    11·2 answers
  • small town whose population was 18,395 ten years ago, has lost 270 inhabitants each year since then. what is the present populat
    14·1 answer
  • How to find 18% of 3000​
    8·2 answers
  • Which angle is coterminal with a 110-degree angle
    13·2 answers
  • For each one-year period after a car was purchased, its value at the end of the year was 17% less than its value at the beginnin
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!