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Otrada [13]
3 years ago
6

What is 1/3 out of 1/3x-5/3

Mathematics
1 answer:
valentina_108 [34]3 years ago
8 0

we are given

\frac{1}{3} x-\frac{5}{3}

we can rewrite it as

\frac{1}{3} *x-\frac{1}{3}*5

we can see that

1/3 is multiple in both terms

so, we can factor it out

and we get

\frac{1}{3} (x-5)...............Answer

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Find the factor of each ff. <br>6z²+12z+18​
frosja888 [35]

Answer:

Step-by-step explanation:

6z² + 12z +1 8​

= 6(z^2 + 2z + 3).

That's it.

8 0
2 years ago
A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.
REY [17]

The question is incomplete as the cost price isn't given. However, taking the cost price as x :

Answer:

Kindly check explanation

Step-by-step explanation:

Given :

A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.

Let :

Cost price when new = x

Cost price when sold = 4/5 * cost price when new

Cost when sold = 4/5 of x = 4x/5

Amount of money lost on the car = (Cost price of car when new - Cost of car when sold)

Hence,

Amount of money lost on the car = (x - 4x/5)

x - 4x/5 = (5x - 4x) / 5 = x / 5

To obtain the exact price, kindly input the omitted cost when new for x.

7 0
3 years ago
Find x. Type only the number.
VMariaS [17]

Answer:

75

Step-by-step explanation:

x= 75

been that the line is perpendicular (the two lines that intersect in such a way that they have a right angle, or a 90 degree angle, between them)

7 0
3 years ago
A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.1 ft/s,
pishuonlain [190]
 <span>let: 
X = the distance of the bottom of the ladder from the wall at any time 
dX/dt = rate of travel of the bottom of the ladder = 1.1 ft/sec 
A = the angle of the ladder with the ground at anytime 
dA/dt = rate of change of the angle in radians per second 

X = 10 cos A 

dX/dt= -10 sin A dA/dt = 1.1 

dA/dt = -1.1/(10 sinA) 

When X = 6; cosA = 6/10; sinA = 8/10 

Therefore: 

dA/dt = -1.1/(10 x 0.8) = -0.1375 radiant per second. </span>
4 0
3 years ago
Nancy bought an extra-large bag of 1,288 beads to make necklaces. When she got home, she found another bag with 784 beads in it.
tekilochka [14]

We are given

Nancy bought an extra-large bag of 1,288 beads to make necklaces

When she got home, she found another bag with 784 beads in it

so, total number of beads =1288+784

total number of beads =2072

now, we have

For one necklace , 56 beads are required

so, 56 beads = 1 necklace

1 bead=\frac{1}{56}necklace

for 2072 beads

2072*1 beads=2072*\frac{1}{56}necklace

2072 beads=37necklace

so,

number of necklaces she can make is 37..........Answer

5 0
3 years ago
Read 2 more answers
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