Question

how many gallons of a 70 acid solution must be mixed with a 3 gal. of a 30% acid solution to make a 55% solution?

Answer 1

Answer:

You would need 5 gallons of a 70% solution

Step-by-step explanation:

You can always use proportions to answer these types of questions.

The numerator will be the amount of acid and the denominator will be the amount of solution

30% of 3 gallons is 0.9.

$\frac{0.9+\frac{7G}{10} }{3+G} =.55\\0.9 + .7G = 1.65 + .55G\\.15G = .75\\G=5$