Answer:
hydrochloric acid reacts with sodium hydroxide to form sodium chloride (the salt) and water.

Explanation:
Sodium chloride is made up of Na+ cations from the base (NaOH) and CI-anions from the acid (HCI).

Hope this helped!

4 0

3 years ago

You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain

Margarita [4]

Answer: 12

Explanation.

This problem was recently posted and deals with the conversion of units,so I give the same answer.

You need to convert the 9 quibs of skvarnick to sleps, to determine how many sleps you have.

The conversion of units is easily undertaken once you build your conversion factors.

Conversion factors are ratios (fractions) equivalent to one, which permits use the identity property of the multiplication to change one unit to a different equivalent one.

Remember that the identity property of multiplication states that any amount multiplied by 1 remains unchanged, i.e.

$a.1=a$

Then, build your conversion factor from the definitions given:

12 sleps is equal to 9 quibs.

12 sleps = 9 quibs

in virtue of the division property of equality, you can divide both sides by 12 sleps and get:

1 = 12 sleps / 9 quibs ← conversion factor

Now you can multiply the amount 9 quibs by the conversion factor, which is equal to 1, to find the equivalent amount of sleps:

identity property: 9 quibs = 9 quibs × 1

substitution property: 9 quibs = 9 quibs × 12 sleps/ 9 quibs

You can see that the unit quibs appear in the numerator and the denominator so it cancels out, and the result will be in sleps.

So, all you have to do now is the operations with the numbers:

9 quibs = (9 × 12 / 9) sleps = 12 sleps ← answer

3 0

3 years ago

How many moles of water would form the reaction of exactly 58.3 grams of magnesium hydroxide

Marat540 [252]

Answer:

$\boxed{\text{2.00 mol}}$

Explanation:

We know we will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

You don't tell us what the reaction is, but we can solve the problem so long as we balance the OH.

M_r: 58.32

Mg(OH)₂ + … ⟶ … + 2HOH

m/g: 58.3

(a) Moles of Mg(OH)₂

$\text{Moles of Mg(OH)$_{2}$} =\text{58.3 g Mg(OH)$_{2}$} \times \dfrac{\text{1 mol Mg(OH)$_{2}$}}{\text{58.32 g Mg(OH)$_{2}$}}\\\\=\text{0.9997 mol Mg(OH)$_{2}$}$

(b) Moles of H₂O

The molar ratio is 2 mol H₂O = 1 mol Mg(OH)₂.

$\text{Moles of H$_{2}$O}= \text{0.9995 mol Mg(OH)$_{2}$} \times \dfrac{\text{2 mol {H$_{2}$O}}}{ \text{1 mol Mg(OH)$_{2}$}}\\\\= \textbf{2.00 mol H$_{2}$O}$

The reaction will form $\boxed{\textbf{2.00 mol}}$ of water.

6 0

3 years ago