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2 years ago

2. Calculate the density of a metal that occupies 17.75 cm and has a mass of 342.93 g. [D = m/V]

Chemistry

1 answer:

satela [25.4K]2 years ago

3 0

Answer:

19.32

Explanation:

the density is given by the mass over volume

the mass In this case is 342.93 and the volume is 17.75

d=342.93g/17.75cm

=19.32g/cm

i hope this helps

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Who is responsible for proposing an influential model of working memory featuring a three-part system that allows individuals to

olga55 [171]

Answer:

The person in charge is: "Alan Baddeley."

Explanation:

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3 years ago

Gasoline has a density of 0.749 g/mL. How many pounds does 19.2 gallons of gasoline weigh? Use significant figures. Do not enter

Yanka [14]

In this question, you are given the gasoline density (0.749g/ml) and volume of the gasoline (19.2 gallons). You are asked the mass of the gasoline in pounds. Then you need to change the grams into pounds and the ml into gallons. The calculation would be:

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3 years ago

Write the full ground state electron configuration of f+.

ANTONII [103]

Answer:- $1s^22s^22p^4$ .

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Second shell is the valence shell for fluorine and so it loses one electron from 2p to form $F^+$ and the electron configuration of the ion becomes $1s^22s^22p^4$ .

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3 years ago

12.A piece of magnesium is in the shape of a cylinder with a height of 5.62 cm

yaroslaw [1]

Answer:

Density, d = 1.779 g/cm³

Explanation:

The density of a material is given by its mass per unit volume.

Here, height of a piece of magnesium cylinder, h = 5.62 cm

Its diameter, d = 1.34 cm

Radius = 0.67 cm

Volume of he cylinder,

$V=\pi r^2 h\\\\\text{Putting the value of r and h, we get :}\\\\V=(\pi \times (0.67)^2\times 5.62)\ cm^3$

$d=\dfrac{m}{V}\\\\d=\dfrac{14.1\ g}{(\pi \times (0.67)^2\times 5.62)\ cm^3}\\\\d=1.779\ g/cm^3$

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2 years ago

Find the empirical formula of the following compounds:

Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus $\frac{mol phosphorus}{ 30.97 g phosphorus}$ = 0.0293 mol

Moles bromine 6.99 g bromine $\frac{mol bromine}{79.90 g bromine}$ =0.0875 mol

The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

To learn more about empirical formula visit:

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8 0

1 year ago