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Alexeev081 [22]
3 years ago
12

Objects take on______ when they are lifted against the force of gravity to a position where they have the potential to fall.

Chemistry
1 answer:
Papessa [141]3 years ago
8 0

A. because you haven't released the object so therefor the potential gravity force applied becomes actual when released.

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How much does one mole of carbon weigh (round to two decimal places)? Make sure your answer has units.
IgorC [24]
The number of atoms present in carbon, specifically Carbon-12, is the number of atoms present in 1 gram of the substance. One moles of the substance weighs approximately 12.01 g/mole. The unit suggests that every mole of carbon weighs 12.01 grams. 
4 0
3 years ago
For this reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ. If two moles of C3H8(g) reacted with excess oxygen,
BartSMP [9]

A) 4400 kj of heat released into surroundings

<h3>Further explanation</h3>

Reaction

C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ

Reaction exothermic( ∆H=-, released heat to surrounding) and for combustion of 1 mole of C3H8

So for two moles of C3H8, the enthalpy :

\tt -2200\times 2=-4400~kJ

7 0
3 years ago
. How many grams of water would require 4400 joules
Alja [10]

Answer:

The specific heat of water is 4.18 J/g C.

Explanation:

q

=

m

C

s

Δ

T

Never forget that!

2200

=

m

⋅

4.18

J

g

⋅

°

C

⋅

66

°

C

∴

m

≈

8.0

g

5 0
3 years ago
A sample of iron is put into a calorimeter (see sketch at right) that contains of water. The iron sample starts off at and the t
Mariulka [41]

Answer:

Therefore, the specific heat capacity of the iron is 0.567J/g.°C.

<em>Note: The question is incomplete. The complete question is given as follows:</em>

<em>A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm. </em>

<em> Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits</em>

Explanation:

Using the formula of heat, Q = mc∆T  

where Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)

When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water

mass of iron  = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C

∆T = 85.0 °C - 27.6 °C = 57.4 °C

mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C

∆T = 27.6°C - 23.0°C = 4.6 °C

Substituting the values above in the equation; Heat lost by Iron = Heat gained by water

59.1 g * c * 57.4 °C  = 100.0 g * 4.184 J/g.°C * 4.6 °C

c = 0.567 J/g.°C

Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.

5 0
2 years ago
To produce energy, nuclear power plants use a process called...
vovangra [49]
I think it’s b but I could be wrong
5 0
3 years ago
Read 2 more answers
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