2
3
−
1
1
=
3
+
3
2
3
x
−
11
=
x
3
+
3
32x−11=3x+3
2
3
−
1
1
=
3
+
3
2
x
3
−
11
=
x
3
+
3
32x−11=3x+3
2
Find common denominator
2
3
−
1
1
=
3
+
3
2
x
3
−
11
=
x
3
+
3
32x−11=3x+3
2
3
+
3
(
−
1
1
)
3
=
3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x+33(−11)=3x+3
3
Combine fractions with common denominator
2
3
+
3
(
−
1
1
)
3
=
3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x+33(−11)=3x+3
2
+
3
(
−
1
1
)
3
=
3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)=3x+3
4
Multiply the numbers
2
+
3
(
−
1
1
)
3
=
3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)=3x+3
2
−
3
3
3
=
3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33=3x+3
5
Find common denominator
2
−
3
3
3
=
3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33=3x+3
2
−
3
3
3
=
3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33=3x+33⋅3
6
Combine fractions with common denominator
2
−
3
3
3
=
3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33=3x+33⋅3
2
−
3
3
3
=
+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33=3x+3⋅3
7
Multiply the numbers
2
−
3
3
3
=
+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33=3x+3⋅3
2
−
3
3
3
=
+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33=3x+9
8
Multiply all terms by the same value to eliminate fraction denominators
2
−
3
3
3
=
+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33=3x+9
3
⋅
2
−
3
3
3
=
3
(
+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33=3(3x+9)
9
Cancel multiplied terms that are in the denominator
3
⋅
2
−
3
3
3
=
3
(
+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33=3(3x+9)
2
−
3
3
=
+
9
2
x
−
33
=
x
+
9
2x−33=x+9
10
Add
3
3
33
33
to both sides of the equation
2
−
3
3
=
+
9
2
x
−
33
=
x
+
9
2x−33=x+9
2
−
3
3
+
3
3
=
+
9
+
3
3
2
x
−
33
+
33
=
x
+
9
+
33
2x−33+33=x+9+33
11
Simplify
Add the numbers
Add the numbers
2
=
+
4
2
2
x
=
x
+
42
2x=x+42
12
Subtract
x
x
from both sides of the equation
2
=
+
4
2
2
x
=
x
+
42
2x=x+42
2
−
=
+
4
2
−
2
x
−
x
=
x
+
42
−
x
2x−x=x+42−x
13
Simplify
Combine like terms
Multiply by 1
Combine like terms
=
4
2
x
Answer:
Step-by-step explanation:
Given Equation:
x^3- 4x^2 + 2x+ 10 = x^2 - 5x-3
which simplifies to
x^3- 5x^2 + 7x+ 13 = 0
Given one of the roots is x = 3x+2i, the conjugate is therefore x = 3-2i.
The product is real, (x-3+2i)(x-3-2i) = x^2-6x+13
The other root can therefore be obtained by long division
(x^3- 5x^2 + 7x+ 13)/(x^2-6x+13) = x+1, or x=-1
Therefore the three roots are:
{x=3-2i, x=3+2i, x=-1 }
Answer:
196
Step-by-step explanation:
Surface area of a cuboid:
2 ( lw + wh + hl)
L = Length
W = Width
H = Height
Area of the base = 30 = lw; So we could take the length as 15 cm and width as 2 cm.
Volume = lwh; 15 x 2 x (4); So 4 is the height
So, 2 ( lw + wh + hl)
= 2 (15 x 2 + 2 x 4 + 4 x 15)
= 2 (30 + 8 + 60)
= 2 (98)
= 196 is the surface area of cuboid
The sequence: 9, 4, 3
The largest number in this sequence is 9.
This is because 9 is of greatest value, being farther from 0 than the numbers 3 and 4.
The smallest number in this sequence is 3.
This is because 3 is of least value, being closer to 0 than the numbers 4 and 9.
Knowing this, we can answer the first question- "Is the first digit the largest or the second digit the smallest?"
9 is the first digit in this sequence, and it is the largest.
4 is the second digit in this sequence, and it is not the smallest. 3 is the smallest value in the sequence, but it is not the second digit.
This means that "the first digit is the largest" is the correct answer to the first question.
Even numbers result in integers, numbers without decimals/fractions, when divided by 2.
3 is an odd number, since it does not result in an integer when divided by 2.
3 is the third number in this sequence.
9 is also an odd number for the same reason.
9 is the first number in this sequence.
Knowing this, we can answer the second question- "Is the third digit even or the first digit odd?"
3 is the third digit in the sequence, and it is odd, not even.
9 is the first digit in the sequence, and it is odd.
This means that "the first digit is odd" is the correct answer to the second question.
Answers:
1) The first digit, 9, is the largest digit in the sequence.
2) The first digit, 9, is odd.
Hope this helps!
Answer:
see below
Step-by-step explanation:
at least one x-intercept - where it crosses the x axis- They both have at least one x intercept
at least one y-intercept - where it crosses the y axis- they both have at least one
an oblique asymptote or slant asymptote- when the degree of the polynomial in the numerator is higher than the denominator - this is true
a vertical asymptote - they both have a vertical asymptote
the domain - is all real values except x = -3 in one case and x=3 in the other
