Write an equation that represents the line
1 answer:
You might be interested in
Answer: There are 40 dentists who would recommended Sparkly toothpaste to their patients .
Step-by-step explanation:
Since we have given that
Out of 20 dentists, a survey was taken of about Sparkly toothpaste,
Number of dentists recommended Sparkly toothpaste to their patients = 16
Percentage of dentists who recommended Sparkly toothpaste to their patients be
Out of 30 dentists, a survey was taken of about Sparkly toothpaste,
Number of dentists recommended Sparkly toothpaste to their patients = 24
Similarly,
Percentage of dentists who recommended Sparkly toothpaste to their patients be
Now, we have asked to find the number of dentists recommended Sparkly toothpaste to their patients if survey was taken of 50 dentists.
As we have seen that there is always 80% of total number of dentists surveyed have recommended Sparkly toothpaste to their patients ,
so, According to this pattern , we get that
Hence, there are 40 dentists who would recommended Sparkly toothpaste to their patients .
Answer:
a) The boundaries are
b) The boundaries are .
c) The boundaries are .
d) The boundaries are .
Step-by-step explanation:
Z-score:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
a. The middle 20% from the 80% in the tails.
The middle 20% is between the 50 - (20/2) = 40th percentile and the 50 + (20/2) = 60th percentile:
40th percentile: Z has a pvalue of 0.4, so Z = -0.253.
60th percentile: Z has a pvalue of 0.6, so Z = 0.253.
The boundaries are .
b. The middle 50% from the 50% in the tails.
The middle 50% is between the 50 - (50/2) = 25th percentile and the 50 + (50/2) = 75th percentile:
25th percentile: Z has a pvalue of 0.25, so Z = -0.675.
75th percentile: Z has a pvalue of 0.75, so Z = 0.675.
The boundaries are .
c. The middle 95% from the 5% in the tails.
The middle 95% is between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile:
2.5th percentile: Z has a pvalue of 0.025, so Z = -1.96.
97.5th percentile: Z has a pvalue of 0.975, so Z = 1.96.
The boundaries are .
d. The middle 99% from the 1% in the tails.
The middle 99% is between the 50 - (99/2) = 0.5th percentile and the 50 + (99/2) = 99.5th percentile:
0.5th percentile: Z has a pvalue of 0.005, so Z = -2.575.
99.5th percentile: Z has a pvalue of 0.995, so Z = 2.575.
The boundaries are .