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balandron [24]
4 years ago
8

Negative six and one third plus twenty over three

Mathematics
1 answer:
nydimaria [60]4 years ago
6 0

Answer:

1/3

Step-by-step explanation:

-6+(-1/3)= -19/3

-19/3 + 20/3 = 1/3

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Help will name Brainliest
11111nata11111 [884]

Answer:

x = \frac{\sqrt{22} }{2}

Step-by-step explanation:

Using the Pythagorean Theorem we can solve this problem.

The legs of the triangle will be the same (the dashes in the middle of the line indicates they are the same).

The Pythagorean Theorem will look like this:

a^{2}+a^{2}  = (\sqrt {11})^{2}

Now, let's find a:

2a^{2} = 11                The square of a radical will be whatever is under the arch

a^{2}=\frac{11}{2}                  Divide 11 by 2

\sqrt{a^{2} } = \sqrt{\frac{11}{2} }           Square root both sides

a = \frac{\sqrt{22} }{2}

Therefore, the length of side x is equal to \frac{\sqrt{22} }{2}.

Hope this helps!!

8 0
2 years ago
Can someone help me with this?! thanks!!
Vera_Pavlovna [14]

Answer:

you literally just translate each shape by the number of squares specified.

Step-by-step explanation:

for example, move shape 1 5 squares to the right, then 4 down. it will be in the middle area of quadrant 1 (where it already is).

4 0
3 years ago
Read 2 more answers
How do I factor this problem
Keith_Richards [23]

Answer:

−(3x−2)(7x+4)

Step-by-step explanation:

4 0
3 years ago
Given: circle k(O), m AM=125°, m EF=31°, m∠MAF=75°. Find: m∠AME
Bess [88]

Answer:

58°

Step-by-step explanation:

If m AM=125°, then m∠AOM=125°.

If m∠MAF=75°, then m∠MOF=150° (because central angle MOF subtends on the same arc as inscribed angle MAF).

Thus,

m∠FOA=360°-150°-125°=85°.

If mEF=31°, then m∠EOF=31° (as central angle subtended on the arc EF).

Hence,

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Angle EOA is central angle subtended on arc EA, angle AME is inscribed angle subtended on arc AE, thus

m∠AME=1/2m∠EOA=58°.

7 0
4 years ago
X+4/2=13 whats x equal
Svetlanka [38]

Answer:

X=11

Step-by-step explanation:

6 0
3 years ago
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