Answer:
It all depends on whether the smaller cylinder is wider than the taller one. If that is the case, then they would have the same volume, roughly, because they would still take up the same amount of space, just in different shapes. If they are the exact same width, then the taller one would have the larger volume, since it would have a larger volume, because it would take up more space.
Step-by-step explanation:
Acceleration=((final velocity)-(initial velocity))÷ time = (change in velocity)÷ time
Answer:
g(-2)=3
g(0)=-5
g(3)=2
Step-by-step explanation:
g(-2)= -2(-2)+ 3(-2) - 5
4-6-5
2-5
g(-2)=3
g(0)= -2(0) + 3 (0)-5
0+0-5
g(0)=-5
g(3)= -2(3) + 3(3)-5
-6+9-5
3-5
g(3)=2
Step-by-step explanation:
Total no. of students = 40
Total no. of girls = 22
Total no. of boys = 40 - 22 = 18
No. of girls walking to school = 9
No. of girls who cycle to school = 22 - 9
No. of boys who cycle to school = 7
No. of students who take the bus = 10
(6 boys and 4 girls)
No. of boys who walk to school = 18 - (7 + 6) = 5
Total no. of students who walk to school = 9 + 5 = 14
Not sure if you can do this but it sounds like a velocity/time/distance equation.
d=vt
v=d/t
t=d/v
70 w/m = t
15 pages - 350 w/p
She can type 70 words per minute (w/m). There are 350 words per page (w/p). She needs 15 pages. So first you have to find how many words she can type in one hour. 60 minutes in an hour, she can type 70 w/p.
60x70=4,200 words per hour (w/h).
Next you should find out how many words on 15 pages total.
350x15= 5,250.
I would put 4,200/5,250 as a fraction to gage how much she has left. She has most of it done already in ONE HOUR. Reduced, she has done 4/5s of the essay. Now you just need to get 1/5 of 5250, which is 1050.
She needs to do 1050 words. If one minute is 70, do 1050/70 which is 15.
The answer is 1 hour and 15 minutes.
I think... ;)
