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gayaneshka [121]
2 years ago
7

Which twos ratios represent quantities that are proportional?

Mathematics
1 answer:
Inessa05 [86]2 years ago
8 0

Answer: it’s 10/15 and 14/21 ;)

Step-by-step explanation:

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The difference from home to
Amanda [17]

Answer:

\frac{3}{8}\ mile

Step-by-step explanation:

-Amy walks a distance of 7/8 mile

-Tom walks a distance of 4/8 mile.

#We immediately notice that Amy has walked a longer distance than Tom.

We subtract Tom's distance from Amy's to find how much further Amy walked;

\bigtriangleup d=d_A-d_T\\\\=\frac{7}{8}-\frac{4}{8}\\\\=\frac{3}{8} mile

Hence, Amy has walked 3/8 miles further than Tom has.

6 0
2 years ago
X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y
andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}

Part b.

Consider V(3X + 2Y)

\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

3 X+2 Y \sim N(18,77)

Thus,

P(3 X+2 Y < 18)=0.5

Part d.

Consider P(3X + 2Y < 28)

Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}

\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0
1 year ago
Last Saturday, Camila practiced her dance routines for her upcoming competition. She spent some time practicing her tap routine,
Natalka [10]

Answer:

t = 28 minutes

Step-by-step explanation:

Last Saturday, Camila practiced her dance routines for her upcoming competition. She spent some time practicing her tap routine, and then she spent 17 minutes practicing her hip-hop routine. In all, she practiced for 45 minutes. Let t be the number of minutes that Camila practiced her tap routine. Write and solve an equation to find t.

45 minutes = Number of minutes for hip-hop routine + Number of minutes for tap dance

The equation is given as

45 = 17 + t

Solving for t

t = 45 - 17

t = 28 minutes

Shes spent 28 minutes tap dancing

4 0
2 years ago
there are 12 boys and 10 girls in the gym class. If 6 more boys joined , how many more girls are needed to stay at the same rati
Travka [436]
Hope this helps good luck ☺

4 0
3 years ago
Harry used 84% of the money in his savings account to buy a used to it like that costume $1050 I want your money is left in Harr
Ratling [72]
Are you saying that $1050 was the initial amount of money in the savings account? If so then you'd find 84% of 1050, which is 1050*.84. (.84 is the decimal version of 84%)
8 0
3 years ago
Read 2 more answers
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