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hoa [83]
2 years ago
12

Daniela recorded the low temperatures during the school day last week and this week. Her results are shown in the table below. L

ow Temperatures during the School Day This Week and Last Week Low Temperatures This Week (mc015-1.jpg) 42 38 45 46 39 Low Temperatures Last Week (mc015-2.jpg) 56 58 52 62 62 Daniela used the steps below to find a relationship between the difference in the mean temperatures and the mean absolute deviations of the data sets. This Week Last Week Step 1 Find the mean. mc015-3.jpg Find the mean. mc015-4.jpg Step 2 Find the mean absolute deviation. mc015-5.jpg Find the mean absolute deviation. mc015-6.jpg Step 3 Find the ratio of the differences of the means compared to the mean absolute deviation. mc015-7.jpg Find the ratio of the differences of the means compared to the mean absolute deviation. mc015-8.jpg Step 4 The difference in the means is about mc015-9.jpg times the mean absolute deviations. In which step did Daniela make the first error
Mathematics
2 answers:
AleksAgata [21]2 years ago
7 0
Daniela made her error on step 3 because it says: <span>
<span>"Find the ratio of the differences of the means compared to the mean absolute deviation.
</span><span>
She didn't find the difference between the today and last week means. She just put the mean as a whole.</span></span>
liberstina [14]2 years ago
7 0
<span> Daniela recorded the low temperatures during the school day last week and this week. Her results are shown in the table below. Low Temperatures during the School Day This Week and Last Week Low Temperatures This Week (mc015-1.jpg) 42 38 45 46 39 Low Temperatures Last Week (mc015-2.jpg) 56 58 52 62 62 Daniela used the steps below to find a relationship between the difference in the mean temperatures and the mean absolute deviations of the data sets. This Week Last Week Step 1 Find the mean. mc015-3.jpg Find the mean. mc015-4.jpg Step 2 Find the mean absolute deviation. mc015-5.jpg Find the mean absolute deviation. mc015-6.jpg Step 3 Find the ratio of the differences of the means compared to the mean absolute deviation. mc015-7.jpg Find the ratio of the differences of the means compared to the mean absolute deviation. mc015-8.jpg Step 4 The difference in the means is about mc015-9.jpg times the mean absolute deviations. In which step did Daniela make the first error? well lets get to it so step 3 was  an error because 58 cant go into 15 so your final answer is step 3 have an amazing day all of you

</span>
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Let <em>S</em> be the sum of the integers 25-210:

<em>S</em> = 25 + 26 + 27 + … + 208 + 209 + 210

Let <em>S₃</em>, <em>S₄</em>, and <em>S₁₂</em> denote the sums of the integers in <em>S</em> that are multiples of 3, 4, or 12, respectively. We'll also count how many terms each sum involves; it'll be useful later.

<em>S₃</em> = 27 + 30 + 33 + … + 204 + 207 + 210 … … … (<u>62</u> terms)

<em>S₃</em> = 3 (9 + 10 + 11 + … + 68 + 69 + 70)

<em>S₄</em> = 28 + 32 + 36 + … + 200 + 204 + 208 … … … (<u>46</u> terms)

<em>S₄</em> = 4 (7 + 8 + 9 + … + 50 + 51 + 52)

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Let's look at <em>S₃ </em>:

<em>S₃</em> = 3 (9 + 10 + 11 + … + 68 + 69 + 70)

By reversing the order of the sum, we get

<em>S₃</em>* = 3 (70 + 69 + 68 + … + 11 + 10 + 9)

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9 + 70 = 79

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and so on. Then

<em>S₃</em> + <em>S₃</em>* = 3 (79 + 79 + 79 + … + 79 + 79 + 79)

or

2<em>S₃</em> = 3 × <u>62</u> × 79   ==>   <em>S₃</em> = 7,347

We can compute the other two sums in the same way.

<em>S₄</em> = 4 (7 + 8 + 9 + … + 50 + 51 + 52)

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<em>S₁₂</em>* = 12 (17 + 16 +15 + … + 5 + 4 + 3)

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