Daniela recorded the low temperatures during the school day last week and this week. Her results are shown in the table below. L
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Answer:
Check the explanation
Step-by-step explanation:
The null and alternative hypotheses in symbols and words are as follows:
: p ≤ 0.06 (There has been no change in the contribution rate due to addition of the mailing labels)
: p > 0.06 (The addition of the mailing labels has increased the contribution rate)
Test Statistics
The following information is provided: The sample size is N = 75000, the number of favorable cases is X = 5625, and the sample
The z-statistic is computed as follows:
- (1 -
Test statistic z = 17.297
P-value
P-value corresponding to z = 17.297 for a two tailed test is obtained using standard normal table.
p-value = 0.0000
90% Confidence Interval Calculation
Kindly check the attached image below.
Conclusion
Since p-value = 0.0000 < α = 0.05, we reject null hypothesis .
At 0.05 significance level, there is enough evidence to conclude that the addition of the mailing labels has increased the contribution rate.
Since the 90% confidence interval (0.073, 0.077) does not contain the hypothesized value 0.06, the result is significant and we reject null hypothesis.
In other words, at 0.10 significance level, there is enough evidence to conclude that the addition of the mailing labels has increased the contribution rate.
