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erma4kov [3.2K]
4 years ago
11

find the work done in moving an object along a vector r = 3i + 2j - 5k if applied force is F = 2i - j -k

Physics
1 answer:
rosijanka [135]4 years ago
7 0
We need to know the distance ... how far the force
moves the object along the vector  3i+2j-5k.
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Answer:

Length = 2.32 m

Explanation:

Let the length required be 'L'.

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Resistance of the resistor (R) = 3.7 Ω

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Resistivity of the material of rod (ρ) = 1.8\times 10^{-5}\ \Omega\cdot m

First, let us find the area of the circular rod.

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R=\rho( \frac{L}{A})

Express this in terms of 'L'. This gives,

\rho\times L=R\times A\\\\L=\frac{R\times A}{\rho}

Now, plug in the given values and solve for length 'L'. This gives,

L=\frac{3.7\ \Omega\times 1.13\times 10^{-5}\ m^2}{1.8\times 10^{-5}\ \Omega\cdot m}\\\\L=\frac{4.181}{1.8}=2.32\ m

Therefore, the length of the material required to make a resistor of 3.7 Ω is 2.32 m.

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