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erma4kov [3.2K]
4 years ago
11

find the work done in moving an object along a vector r = 3i + 2j - 5k if applied force is F = 2i - j -k

Physics
1 answer:
rosijanka [135]4 years ago
7 0
We need to know the distance ... how far the force
moves the object along the vector  3i+2j-5k.
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Volume.

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Each milligram of glucose has the same amount of energy available to do work. The series B test tubes produced more bacteria per
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Answer:

The series A test tube has some left amount of glucose left in it.

Explanation:

Let's assume that a fixed amount of glucose is synthesized, for the fixed quantity the bacteria produced in A and B be x and y respectively,

Therefore, the condition on x and y is,    y > x  as the no. of bacteria present in B is greater.

As a result B would require a greater amount of energy for its functioning, these energy would be derived from the already fixed amount of glucose present.

A test tube would also require the energy for its x number of bacteria, but it is less than that of B.

Therefore, there would be some unused glucose left in Test Tube Series A which has unused energy.

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3 years ago
Two iron weights, one twice the mass of the other, are dropped from the top of a building. Compared with the lighter weight, the
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The twice as heavy weight will hit the ground with more force, or impact.
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3 years ago
Read 2 more answers
According to coulombs law, what will happen to the force between two charged particles if the magnitude are increased by 6 times
seropon [69]

Answer: The electrostatic force will be the same

Explanation:

According to Coulomb's Law, when two electrically charged bodies come closer, appears a force that attracts or repels them, depending on the sign of the charges of this two bodies or particles.  

In this sense, this law states the following:

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"  

 

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}  (1)

Being K is a proportionality constant.  

Now, if each q_{1} and q_{2} are increased by 6, and the distance between them as well, we will have the following:

F_{E}= K\frac{6 q_{1}. 6 q_{2}}{(6d)^{2}}  (2)

F_{E}= 36 K\frac{q_{1}. q_{2}}{36d^{2}}  (3)

Simplifying:

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}  (4)

Comparing (1) with (4) we can see the electrostatic force is the same.

4 0
4 years ago
A hummingbird flies 1.2 m along a straight path at a height of 3.4 m above the ground. Upon spotting a flower below, the humming
Viefleur [7K]

Answer:1.84

Explanation:

Given

Humming bird travels 1.2 m along a straight line at height of 3.4 m

Now bird drops 1.4 m to hover in front of the flower

So bird net displacement is

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displacement=\sqrt{3.4}

=1.84

7 0
3 years ago
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