When distances were carefully measured from the Earth to globular clusters above and below the Milky Way plane (where our view o
1 answer:
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Answer:
Approximately (assuming that the partner is holding the other end of the coil stationary.)
Explanation:
In a standing wave, an antinode is a point that moves with maximal amplitude, while a node is a point that does not move at all. There is an antinode between every two adjacent nodes. Likewise, there is a node between every two adjacent antinodes.
The side of the spring that is being shaken moving with maximal amplitude. Hence, that point on this spring would also be an antinode. In contrast, the side of the spring that is held still (does not move at all) would be a node.
There would be a node between:
- the antinode at the end of the spring that is being shaken, and
- the antinode between the two ends of this spring.
Overall, the nodes and antinodes on this spring would be:
- node at the end that is being held still,
- antinode (as mentioned in the question),
- node (inferred, not mentioned in the question), and
- antinode at the end that is being shaken.
The distance between two adjacent nodes is equal to one-half (that is, ) the wavelength of the wave. The distance between a node and an adjacent antinode is one-quarter (that is,
) of the wavelength of the wave.
Thus, if the wavelength of the wave in this question is , the length of this spring would be:
.
The question states that the length of this coiled spring is . In other words,
. The wavelength of this wave would be
.
The frequency of this wave is the number of cycles in unit time:
.
Hence, the speed of this wave would be:
.
Answer:
Explanation:
Project mass m=3.8 kg
Initial speed vi= 0m/s
Final speed vf= 9.3×10³ m/s
Force F=9.3×10⁵N
To find
Time t
Solution
From Newtons second law we know that
∑F=ma
Where m is mass
a is acceleration
We can write this equation as
∑F=m(Δv/Δt)
Rearrange this equation to find time t
So
Substitute the given values
Answer:
Assumption: the air resistance on this ball is negligible. Take .
a. The momentum of the ball would be approximately two seconds after it is tossed into the air.
b. The momentum of the ball would be approximately three seconds after it reaches the highest point (assuming that it didn't hit the ground.) This momentum is smaller than zero because it points downwards.
Explanation:
The momentum of an object is equal its mass
times its velocity
. That is:
.
Assume that the air resistance on this ball is negligible. If that's the case, then the ball would accelerate downwards towards the ground at a constant . In other words, its velocity would become approximately
more negative every second.
The initial velocity of the ball is . After two seconds, its velocity would have become
. The momentum of the ball at that time would be around
.
When the ball is at the highest point of its trajectory, the velocity of the ball would be zero. However, the ball would continue to accelerate downwards towards the ground at a constant . That's how the ball's velocity becomes negative.
After three more seconds, the velocity of the ball would be . Accordingly, the ball's momentum at that moment would be
.