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3 years ago

What happens when a substance undergoes a physical change?

Physics

2 answers:

vodka [1.7K]3 years ago

8 0

A: Some physical properties change, but the substance keeps its identity.

zlopas [31]3 years ago

8 0

Answer;

A: Some physical properties change, but the substance keeps its identity.

Explanation;

Physical changes occur when objects or substances undergo a change that does not change their chemical composition. This is different from chemical change in which the composition of a substance changes or one or more substances combine or break up to form new substances.

A physical change in a substance doesn't change what the substance is. In a chemical change where there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.

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15.0 N

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3 years ago

Physics <br><br> I’ll give brainiest! :)

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3 years ago

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1. According to paragraph 3 in the text, MOST of the electromagnetic waves from

Fed [463]

Answer:

Most of the EM waves from the sun that reach Earth are infrared waves, visible light, and UV radiation.

Explanation:

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3 years ago

in a solar system far, far away the sun's intensity is 200 w/m2 for an inner planet located a distance r away. what is the sun's

GarryVolchara [31]

The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.

<h3>What is the Inverse Square Law formula?</h3>

The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as

$\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}$

Where

I₁ = Intensity at distance 1 (W/m²)
I₂ = Intensity at distance 2 (W/m²)
d₁ = distance 1 from a light source (m)
d₂ = distance 2 from a light source (m)

Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?

By using the inverse square law formula, the sun's intensity for an outer planet is

$\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}$

$\frac{200 }{I_{2} } = \frac{(6r)^{2} }{r^{2}}$

$\frac{200 }{I_{2} } = \frac{36r^{2} }{r^{2}}$

$I_{2} = \frac{200} {36}$

I₂ = 5.55 W/m²

Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².

Learn more about intensity of light here:

brainly.com/question/13155277

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1 year ago

the projectile thrown with the same initial velocity , one at an angle theta and the other at an angle 90-theta can both project

bixtya [17]

Answer:

If theta is equal to 90, then both projectiles strike at the same distance from the projection point and projectiles are in air for the same time interval.

Explanation:

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2 years ago