4 years ago

What the answer to this???

1 answer:

8 0

Answer:

they are similar because you have to in both equations you have to multiply 1/2 by bh

they are different because the trapezoid base is added to itself and multiplied by 1 and 2

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emmainna [20.7K]

It depends on how you look at it and what you are trying to find

8 0

3 years ago

BARSIC [14]

To answer this, you will first need to simply the expressions.

$4\sqrt{27} = 12\sqrt{3}$

$6\sqrt{75} = 30\sqrt{3}$

Now with the expressions simplified, you'll add the two together getting $42\sqrt{3}$

7 0

3 years ago

DerKrebs [107]

512 c2 so A sorry if im wrong

7 0

3 years ago

Dvinal [7]

The linear approximation to $f(x)$ near $x=16$ is

$L(x)=f(16)+f'(16)(x-16)$

We have

$f(x)=\sqrt x\implies f(16)=4$

$f'(x)=\dfrac1{2\sqrt x}\implies f'(16)=\dfrac18$

$\implies L(x)=4+\dfrac18(x-16)=\dfrac x8+2$

Then

$f(16.2)\approx L(16.2)\iff\sqrt{16.2}\approx\dfrac{16.2}8+2$

$\implies\boxed{\sqrt{16.2}\approx4.025=\dfrac{161}{40}}$

5 0

3 years ago

Kazeer [188]

I believe 3 hours, not sure. Wait and see if someone else answers!

6 0

3 years ago