All categories

2 years ago

3x< 21 fill in the blank x < ____

1 answer:

7 0

To solve this problem, you need to have x alone on one side of the inequality. To do this, you need to undo the multiplication that is bonding 3 and x together. To undo this, you need to divide both sides by 3.

This results in the inequality x<7.

Your final answer is x<7.

You might be interested in

Find the product. Write your answer in scientific notation. (3 x 10^2)×(4×10^5)

suter [353]

Answer:

12 * 10 ^ 7

Step-by-step explanation:

3 * 10 ^ 2 * 4 * 10 ^5

= 12 * 10^ 2 + 5

= 12 * 10 ^ 7

Hope it will help :)

7 0

2 years ago

Simplify the following expression:<br> 12a+9b2a-13a2b2+4ab2-16a

Rudiy27

$12a+9b^2a-13a^2b^2+4ab^2-16a= \\ =12a-16a+9ab^2+4ab^2-13a^2b^2= \\ =-4a+13ab^2-13a^2b^2= \\ =a(-4+13b^2-13ab^2)$

8 0

3 years ago

Read 2 more answers

Two lines, A and B, are represented by the equations given below!

lara [203]

Answer:

The solutions to the system of equations are:

$y=-8,\:x=-4$

Thus, option C is true because the point satisfies BOTH equations.

Step-by-step explanation:

Given the system of the equations

$\begin{bmatrix}y=x-4\\ y=3x+4\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}y-x=-4\\ y-3x=4\end{bmatrix}$

$y-3x=4$

$-$

$\underline{y-x=-4}$

$-2x=8$

$\begin{bmatrix}y-x=-4\\ -2x=8\end{bmatrix}$

solve for x

$-2x=8$

Divide both sides by -2

$\frac{-2x}{-2}=\frac{8}{-2}$

$x=-4$

$\mathrm{For\:}y-x=-4\mathrm{\:plug\:in\:}x=-4$

$y-\left(-4\right)=-4$

$y+4=-4$

$y=-8$

The solutions to the system of equations are:

$y=-8,\:x=-4$

Thus, option C is true because the point satisfies BOTH equations.

8 0

3 years ago

What's 6/7 written as a fraction with a denominator of 42

uysha [10]

So we are trying to find the numerator of 42 in relation of 6/7.

42 divided by 7= 6 So 6 x 6 from the numerator of 6/7 = 36.

So 6/7 written as a fraction with a denominator of 42 is 36/42.

6 0

2 years ago

Read 2 more answers

What is the vertex of f(x)=-x^2-8x

frez [133]

$\bf f(x) = -x^2-8x\implies f(x) = -x^2-8x+0 \\\\[-0.35em] ~\dotfill\\\\ \textit{vertex of a vertical parabola, using coefficients} \\\\ f(x)=\stackrel{\stackrel{a}{\downarrow }}{-1}x^2\stackrel{\stackrel{b}{\downarrow }}{-8}x\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{-8}{2(-1)}~~,~~0-\cfrac{(-8)^2}{4(-1)} \right)\implies \left( -4~~,~~0+\cfrac{64}{4} \right)\implies (-4~,~16)$

7 0

3 years ago

Read 2 more answers