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Alex777 [14]
3 years ago
11

Pls answer with real answers thank you (2)

Mathematics
2 answers:
Nana76 [90]3 years ago
6 0

Answer:

So I'm not gonna give you the answer cause this is pretty easy math but I will walk you through it.

Step-by-step explanation: First multiply any 2 numbers you want. Write that number down and multiply the next 2 numbers and write it down. Add the 2 numbers you got from multiplying. With the number left over just add it to the equation.

lilavasa [31]3 years ago
3 0

Answer:

i think 84 or 90

Step-by-step explanation:

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adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

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x=y^2+4y\\ y^2+4y-x=0\\&#10;y^2+4y+4-4-x=0\\&#10;(y+2)^2=x+4\\&#10;y+2=\sqrt{x+4} \vee y+2=-\sqrt{x+4}\\&#10;y=-2+\sqrt{x+4} \vee y=-2-\sqrt{x+4}\\

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