2 years ago

The sum of the ages of dauda and his brother is 2. Five years ago dauda was 3times as old as his brother . How old are they now

Mathematics

1 answer:

Aloiza [94]2 years ago

8 0

Answer:

$dauda = x \\ his \: brother = y \\ x + y = 2 \: \: \: (i) \\ 5(3x + y) = 5 \: \: \: (ii) \\ 15x + 5y = 5$

I don't really remember this very well, because it confusing me

You might be interested in

What is the value of x in the equation x - y = 30, when y = 15?

igor_vitrenko [27]

Answer:

o 200

fctvtvtv

Step-by-step explanation:

O200 o200

6 0

2 years ago

4a²-8ab+4b=????????????

GuDViN [60]

Step-by-step explanation:

4a² - 8ab + 4b²

= (2a)² - 2 * 2a * 2b + (2b) ²

= (2a - 2b) ²

Hope it helps :)

3 0

2 years ago

It takes 200 minutes to jog 4 miles how many minutes does it take to jog 1 mile

blsea [12.9K]

Answer:

50 minutes

Step-by-step explanation:

200÷4 = 50 minutes

4 0

2 years ago

Read 2 more answers

Need help plz, show work too

disa [49]

Answer:

Hope it helps this is an isosceles triangle

4 0

3 years ago

Read 2 more answers

Factorise 9(a+b)^2 + (a+b) -8

frutty [35]

Answer:

$(9a+9b-8)(a+b+1)$

Step-by-step explanation:

$9(a+b)^2 + (a+b)-8$

Expand $(a+b)^2$

$9(a^2+2ab+b^2)+a+b-8$

$9a^2+18ab+9b^2+a+b-8$

Now it is time to think.

Once

$9a^2=9a \cdot a$

$9b^2=9b \cdot b$

$18ab=9ab+9ab$

$-8=-8 \cdot 1$

We can get something in the format

$(9a+9b-8)(\text{some expression here})$

From the conclusions above,

$(9a+9b-8)(a+b+1)$

8 0

2 years ago