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inessss [21]
4 years ago
12

Determine the number of outcomes in the event. Decide whether the event is a simple event or not. You randomly select one card f

rom a standard deck of 52 playing cards. Event Upper A is selecting a red four. nothing nothing
Mathematics
1 answer:
Marat540 [252]4 years ago
3 0

Answer:

No we can consider A as single event. See the explanation below

Step-by-step explanation:

Let's define the event A as:

A=" Select a 4 from a standard deck of 52 cards"

We know that in a standard deck we have 4 different types of 4, spade, heart, diamond and club.

And by definition of simple event we need to have just one possible outcome in the experiment, and on this case we have 4 possible options for event A, so for this reason the event A can't be considered as simpl event.

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Determine the slope <br><br> 2y-4x=1
Maurinko [17]

Answer:

2

Step-by-step explanation:

The equation is mx+b=y

The equation is not simplified yet.

2y-4x=1

Add 4x to both sides

2y=1+4x

Divide by 2

1/2+2x

For this just identify. M=slope. The number next to the x is 2. So the answer is 2

3 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST<br> plsss help
ExtremeBDS [4]

Answer:

heyyy I will try My best to help you

3 0
3 years ago
Help?? I seriously don’t understand?
Anvisha [2.4K]

Answer:

A

Step-by-step explanation:

3(x-2)

Replace x as 12

3(12-2)

3(10)

3 times 10

30

7 0
3 years ago
Each day, Robin commutes to work by bike with probability 0.4 and by walking with probability 0.6. When biking to work injuries
kvasek [131]

Answer:

64.65% probability of at least one injury commuting to work in the next 20 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}&#10;

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Each day:

Bikes to work with probability 0.4.

If he bikes to work, 0.1 injuries per year.

Walks to work with probability 0.6.

If he walks to work, 0.02 injuries per year.

20 years.

So

\mu = 20*(0.4*0.1 + 0.6*0.02) = 1.04

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}&#10;

P(X = 0) = \frac{e^{-1.04}*1.04^{0}}{(0)!} = 0.3535&#10;

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3535 = 0.6465

64.65% probability of at least one injury commuting to work in the next 20 years

3 0
3 years ago
Can someone pls help me I think I know the answer but still
irakobra [83]

Answer:

b y=9000(1+3.5)20

Step-by-step explanation:

y=a(1+r)t

yer welcome

8 0
3 years ago
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