To simplify the expression, we first open the parenthesis, then we collect all the like terms. Lastly we simplify the like terms to its simplest form. Given that:

$\frac{1}{2}(3x-\frac{2}{3} y)+3(\frac{x}{2}+\frac{1}{2}y )\\\\Firstly, we\ expand\ the\ parenthesis:\\\\=\frac{1}{2}(3x)-\frac{1}{2}(\frac{2}{3} y)+3\frac{x}{2}+3(\frac{1}{2} y)\\$

$=\frac{3}{2}x-\frac{1}{3}y +\frac{3}{2}x+\frac{3}{2} y\\\\ Collecting\ like\ terms:\\\\=\frac{3}{2}x+\frac{3}{2}x-\frac{1}{3}y+\frac{3}{2}y\\\\Adding \ terms:\\\\=3x +\frac{7}{6}y$

6 0

3 years ago

What is the area of the figure above ?

RideAnS [48]

Answer:

256m^2

Step-by-step explanation:

you can cut up the figure.

A1=bh

A1= 24x8

A1=192m^2

A2=bh

A2= bh

A2=8x8

A2=64m^2

A1+A2= Atotal

A=192+64

A=256m^2

4 0

3 years ago