Answer:
![\text{C. }g(x)=(x-5)^2](https://tex.z-dn.net/?f=%5Ctext%7BC.%20%7Dg%28x%29%3D%28x-5%29%5E2)
Step-by-step explanation:
The function
has a phase shift of
to the parent function
. Since
has moved to the right 5 units from the parent function
, we're looking for a value of
.
Therefore, we have:
![g(x)=\boxed{(x-5)^2}](https://tex.z-dn.net/?f=g%28x%29%3D%5Cboxed%7B%28x-5%29%5E2%7D)
If he is the only one that is bowling, it would have to be around 4 games with $1 to spare
21,4,9,19,25,16,27,30,33,15,31 Minimum: Quartile1: Quartile2: Quartile3: Maximum:
bazaltina [42]
Answer:
Minimum:4 Quartile 1:15.5 Quartile 2:21 Quartile 3:26 Maximum:33
Step-by-step explanation:
Order out the numbers least to greatest then find the middle number, the middle number is the median or quartile 2, then you find the middle of the first half, that number would be the 1st quartile, then find the number in the middle of the second half, that is your 3rd quartile, the min is the smallest number max is the largest.
He only used 1/5 of the jar so (1/5*1/4) because he used a fourth of the fifth of the jar the answer is 1/20<span />
<span>A=(2t+1)t^1/2 differentiate both sides w.r.t t to get the solution</span>