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MariettaO [177]
3 years ago
14

What is the solution to the equation below? Round your answer to two decimal places. e^0.3x=0.3

Mathematics
2 answers:
mel-nik [20]3 years ago
7 0

Answer:

x =  - 4.01

Step-by-step explanation:

{e}^{0.3x}  = 0.3 \\  ln( {e}^{0.3x})  =  ln(0.3)  \\ (0.3x)  ln(e)  =  ln(0.3)  \\ 0.3x =  ln(0.3)  \\ x =  \frac{ ln(0.3) }{0.3}  \\ x = -4.01324268109 \\ x =  - 4.01

bearhunter [10]3 years ago
5 0

Answer:-4.01

Step-by-step explanation:

e^0.3x = 0.3

To get rid of the exponential, we take the "In" of bothside.

Ine^0.3x = In0.3

0.3x = In0.3

0.3x = -1.203928

Dividw bothside by 0.3

0.3x/0.3 = -1.203928 / 0.3

x = -4.013

x= -4.01 to two decimal place.

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5. In this diagram, lines AC and DE are parallel,
zhannawk [14.2K]

The length of side DE is 3cm

<h2 /><h3>Parallel line</h3>

Since the line AC is equivalent to DE, hence AC = DE

To get the length of DE, we will need to get the length oF AC using the Pythagoras theorem:

Given the following parameters

Hypotenuse = 5

Opposite = 4

Required

Adjacent side

Substitute the given parameters into the formula of Pythagoras theorem.

AC² = 5² - 4²

AC² = 25 - 16

AC² = 9

AC = 3

Hence the length of side DE is 3cm

Learn more on Pythagoras theorem here: brainly.com/question/12306722

8 0
2 years ago
Tickets to a school play are $4.50 for an adult and $3.00 for a student. If 300 tickets are sold and $1087.50 collected, how man
Kryger [21]

Answer:

<h2>125 tickets for an adult</h2><h2>and 175 tickets for a student</h2>

Step-by-step explanation:

a-\text{number of the tickets for an adult}\\s-\text{number of the tickets for a student}\\\\(1)\qquad a+s=300\\(2)\qquad4.5a+3s=1087.5\\------------\\(1)\\a+s=300\qquad\text{subtstitute}\ s\ \text{from both sides}\\a=300-s\\\\\text{Put it to (2):}\\\\4.5(300-s)+3s=1087.5\qquad\text{use distributive property}\\\\(4.5)(300)+(4.5)(-s)+3s=1087.5\\\\1350-4.5s+3s=1087.5\qquad\text{subtract 1350 from both sides}\\\\-1.5s=-262.5\qquad\text{divide both sides by (-1.5)}\\\\\boxed{s=175}

\text{Put the value of}\ s\ \text{to (1):}\\\\a=300-175\\\\\boxed{a=125}

3 0
2 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
2 years ago
What is the height of a trapezoid with an area of 99 in.2 whose bases are 6 in. and 12 in.?
vladimir1956 [14]

Answer:

trapezoid area = ((sum of the bases) ÷ 2) • height

trapezoid area = ((6 + 12) / 2) * height

trapezoid area = 18 / 2 * height

height = 99/9 = 11

Step-by-step explanation:

7 0
2 years ago
Find b. Question 19 options:<br><br><br>70.1<br><br><br>57.7<br><br><br>31.5<br><br><br>43.8
Reptile [31]

Answer: 57.7

Step-by-step explanation:

6 0
2 years ago
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