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Assoli18 [71]
2 years ago
14

Choose 2 answers: Obtuse triangle Scalene triangle Equilateral triangle Right triangle Acute triangle Isosceles triangle​

Mathematics
1 answer:
nataly862011 [7]2 years ago
6 0

Answer:

Scalene, right triangle

Step-by-step explanation:

its a scalene triangle because all the sides are different, and a right triangle because the box in the corners is what shows whether the angle is a right angle or not.

Hope that makes sense.

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Which of the following statements about the graph of y=3/4x-1 are true?
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What are the statements?
4 0
2 years ago
Oblicz ułamki 2/8=.../4
Marina86 [1]

Answer:


Step-by-step explanation:


7 0
3 years ago
Lynn wants to serve hamburgers at her birthday party if hamburger buns are sold in packages of 8 and hamburger patties are sold
WARRIOR [948]

everyone will get 2 burgers i got this answer by multiplying 8 and 6 and then i divided it by 24 and i got 2



                                                    hope it helps

3 0
3 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
3 years ago
Find the distance between the points (-5, -10) and (2, 4).
Novay_Z [31]
Ok, so I used the equation Y2 (4) - Y1 (-10) over X2 (2) -X1 (-5).
4 - -10 is 14 since if a minus sign is before a negative number, it becomes positive.
Same goes for 2 - -5. It is 7 since the minus sign is before the negative number. Final answer is 14/7 which can be simpflied to 2/1 since 14 divided by 7 =2. So the distance is 14\7, or 2\1.
3 0
3 years ago
Read 2 more answers
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