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Brilliant_brown [7]
3 years ago
6

How to solve the infinite series:

Mathematics
1 answer:
RoseWind [281]3 years ago
6 0
∞
∑3(1/4)ⁿ⁻¹   ==> replace n by consecutive values, starting with 1
ⁿ=¹
f(1) = 3(1/4)⁰ = 3 x 1 (any number raised to o is equal to 1
f(2) = 3(1/4)¹ = 3 x 1/4
f(3) = 3(1/4)² = 3 x (1/4)²
f(4) = 3(1/4)³ = 3 x (1/4)³
f(5) = 3(1/4)⁴ = 3 x (1/4)⁴
And so on and so forth. Then we have found a pattern that is:

f(n) = 3(1/4)ⁿ⁻¹ 
and with this you can find any number providing you know n
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<h3>What are equivalent angles?</h3>

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant. The relevance to these equivalent angles is that they may have equal values for the trigonometric functions, meaning that they are not one-to-one.

If we restrict the domain of the trigonometric functions in any of the four quadrants, we guarantee that they are one-to-one, hence the restricted domains are given as follows:

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More can be learned about trigonometric functions at brainly.com/question/16818112

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