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Usimov [2.4K]
2 years ago
7

How to do this? I confused lol.

Mathematics
2 answers:
Maurinko [17]2 years ago
8 0
Shaded region = triangle - square
First find area of triangle
Formula: (height * base)/2
Height = 5, base = 14
(5 * 14)/2 = 35 cm^2
Now find area of square
Square formula: l * w
Length = 2, width = 2
2 * 2 = 4 cm^2
Now subtract the square from the triangle
35 cm^2 - 4 cm^2 = 31 cm^2
Solution: shaded region is 31 cm^2
NNADVOKAT [17]2 years ago
6 0

Answer:

31 cm²

Step-by-step explanation:

First find the are of the triangle, then subtract the are of the square

Area triangle = 1/2b * h

Area triangle = 1/2(14*5)

Area triangle = 1/2(70)

Area triangle = 35

Now the area of the square

Area square = 2 * 2

Area square = 4

Now subtract

Area shaded = 35 - 4

Area shaded = 31

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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The perimeter of a rectangular painting is 362 CM if the length of the painting is 97 centimeters what is its width
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Answer:

84

Step-by-step explanation:

97+97=194 because a rectangle has 2 long sides.

362-194=168

168/2=84

Width=84 cm

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25x2 - 64 = 0<br> I need help solving this using quadratic function.
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8 0
2 years ago
A nursery has two hundred 7-gallon palm trees to sell, consisting of coconut palm trees, saw palmetto palm trees and christmas p
motikmotik

Total number of trees available to be sold = 200

Selling price of coconut palm trees sell (Pco)= $75 each

Selling price of saw palmetto palm trees sell (Pp) = $45 each

Selling price of christmas palm trees (Pch) = $30 each

Number of saw palmetto palm trees (Np) = 3 × Number of christmas palm trees (Nch)

Let number of coconut palm trees be Nco

Total price paid by developer for all the palm trees = 12,300

So Total number of trees = Nco + Np + Nch

⇒ 200 = Nco + 3×Nch + Nch

⇒ 200 = Nco + 4Nch ................ (i)

Total selling price of trees = Sco × Nco + Sp × Np + Sch × Nch

⇒ 12,300 = 75×Nco + 45×Np + 30×Nch

Dividing above equation by 5

⇒ 2,460 = 15Nco + 9Np + 6Nch

Substituting Np = 3Nch in the above equation

⇒ 2,460 = 15Nco + 9 (3Nch) + 6Nch

⇒ 2,460 = 15Nco + 33Nch ................ (ii)

Mutiply (i) with 15 and subtract from (ii)

⇒ 2,460 - 3,000 = 15Nco + 33Nch - 15Nco - 60Nch

⇒ -540 = 33Nch - 60Nch

⇒ -540 = 27Nch

⇒ Nch=20

If Nch = 20, Np = 3×20 = 60

Since Nco + Np + Nch = 200

⇒ Nco = 200 - (80)

⇒ Nco = 120

Hence, the developer purchased 120 coconut palm trees, 20 christmas palm trees and 60 saw palmetto palm trees.

6 0
3 years ago
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