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olga_2 [115]
3 years ago
13

You save $500 in a retirement account at age 25. it increases an average of 10% per year until you are 65. which formula and res

ult indicates how much money you will have in this account at age 65?
a.500 x (1 + 0.10) ^ (65 - 25) = $22,629.63b.500 x (1 + (0.10 x (65 - 25)) = $2,500 submit
Computers and Technology
1 answer:
Anvisha [2.4K]3 years ago
6 0
Any amount deposited in a bank at today will follow the compound interest formula for a period of time to multiply the amount of money deposited over time. Here too we can use the same formula: i.e

Amount after certain time = Principle * (1 + rate of interest/ number of installments in a year)^( number of installments in a year * time of deposit)

So, the correct formula for the amount at the age of 65 will be:

A = 500 * (1+0.1*/1)^(1*(65-25)) = 500 * (1+0.1/1)^(40*1) = <span>$22,629.63 </span>is the correct answer.
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Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
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Answer:

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#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

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    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

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21

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93

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109

150

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while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

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numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

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At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

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So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

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sum += number; this becomes:

sum = sum + number

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Now the loop breaks and the program moves to the statement:

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       average = 690/10;

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So the entire output of the program is:

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The screenshot of the program and its output is attached.

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