Answer:
Answered below
Explanation:
# Program is written in Java
class WeekHours{
double school;
double fun;
double sleep;
double sports;
WeekHours( ){
school = 0.0;
fun = 0.0;
sleep = 0.0;
sports = 0.0;
}
public void setSchool ( double x){
school = x;
}
public void setFun( double y){
fun = y;
}
public void setSleep( double w){
sleep = w;
}
public void setSports( double z){
sports = z;
}
public void totalHours(){
double tHours = school + fun + sleep + sports;
System.out.print(tHours);
}
}
It’s two ways to analyze data
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There isn't an opening and closing parentheses for the else statement. PM me. I know a lot of batch...
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// recursive function to find sum from 1 to n
int recur_Sum(int n)
{ // base condition
if (n <= 1)
return n;
// recursive call
return n + recur_Sum(n - 1);
}
// main function
int main()
{
// variables
int n;
cout<<"Enter a number:";
// read the number
cin>>n;
// print the sum
cout<<"Sum of first "<<n<<" integer from 1 to "<<n<<" is:"<<recur_Sum(n);
return 0;
}
Explanation:
Read a number from user and assign it to variable "n".Call function recur_Sum() with parameter "n".This function will recursively call itself and find the Sum of first n numbers from 1 to n.Then function will return the sum.
Output:
Enter a number:10
Sum of first 10 integer from 1 to 10 is:55
