Ask question

Ask question

All categories

2 years ago

11

The complementary angle of 59°

2 answers:

Mandarinka [93]2 years ago

7 0

90° - 59° = 31°

31° is your answer

cestrela7 [59]2 years ago

4 0

Complementary means that two angles added up together equal 90 degrees.

Subtract 59 from 90 to get your answer.

90-59= 31

You might be interested in

One morning during the spring break, Jose ran 13 miles up hill in the rain. That afternoon Jose ran up the hill 3 2/3 faster whe

netineya [11]

Answer:

The answer to your question is 13 miles

Step-by-step explanation:

In the question is not mentioned the distance that Jose one during the afternoon, it is only mentioned that he ran faster than in the morning so we can imply that the distance was the same in both occasions, just he ran faster in the afternoon because there was no rain.

6 0

2 years ago

OK, I REALLY NEED ALL OF THIS DONE SOON!

Rudik [331]

Answer: 1. 140 times

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Solve for y in terms of w, x, and z.<br> x = żyw

KonstantinChe [14]

Answer and work down below. Let me know if you have any questions

5 0

3 years ago

294 to the nearest 1000

Viefleur [7K]

294.000 is your answer

3 0

3 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0

2 years ago