<span>$100.00 rounded value
$105.00 rounded value
$110.00 rounded value
For example,
14,494 </span>
<span>To round off the height value to the nearest thousand we can use the expanded from to clarity the position of numbers which is: </span>
<span>10, 000 = ten thousand </span>
<span>4, 000 = thousands </span>
<span>400 = hundreds </span>
<span>90 = tens </span>
<span>4 = ones </span>
<span>Here we can notice than four thousand is the value where the nearest thousands is placed. Hence we can round off the number of 14, 494 into 14, 000. Notice 0-4 rounding off rules.<span>
</span></span>
The answer is B because if you get 5 on the first test then you will have 10 already. if you get at least 1 point on the second then you will have 11 or higher. since the 1st is doubled then the shaded region will retreat by 2 squares for every point less then the maximum you get on the first test.
Since no value is given to Eva, we'll call her x. Justin, then, is 7.50+x. That leaves Emma, who would be Justin (7.50+x) -12. If we add them all together we get 63. So our equation is
x + (7.50+x) + (7.50+x)-12 = 63
Combine like terms
x+x+x + 7.50+7.50-12 = 63
3x + 3 = 63
3x = 60
x = 20
Since we said Eva is x then Eva has 20 dollars.
Justin is 7.50 + x so 7.50+20=
$27.50
Emma is Justin - 12 so 27.50-12= $15.50
Let's check our answer...
15.50+27.50+20 = 63
63=63
It checks!
To answer this, you use the formula 
where
is the simple interest that builds
is the principal (AKA the amount invested/borrowed)
is the interest rate per year
is the lenght of the loan, in years.
In your situation:
![\begin{aligned}I &= (\$3000)(5 \%/\text{year})(3 \text{ years})\\[0.5em]&= (3000)(0.05)(3)\\[0.5em]&= 450\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7DI%20%26%3D%20%28%5C%243000%29%285%20%5C%25%2F%5Ctext%7Byear%7D%29%283%20%5Ctext%7B%20years%7D%29%5C%5C%5B0.5em%5D%26%3D%20%283000%29%280.05%29%283%29%5C%5C%5B0.5em%5D%26%3D%20450%5Cend%7Baligned%7D)
This means there'd be $450 of simple interest due at the end of 3 years.
