Answer:
see below
Step-by-step explanation:
Standard equation for a circle with center h,k and radius r
(x-h)^2 + (y-k)^2 = r^2
so for this one center = (1,2) radius = 4
Answer:
0.06
Step-by-step explanation:
If u need anything let me k ow I don’t have enough info to answer that
Answer:
R is not collinear.
S is collinear.
Step-by-step explanation:
The equation of the graph is given by y =x +2 ........ (1).
Now, the points P and Q having coordinates (5,7) and (-1,1) respectively lie on the graph of the equation (1) because those points satisfy the equation.
Now, if we consider another point R having coordinates (1,-1), then it does not lie on the graph of equation (1) as it does not satisfy the equation.{If you put x=1, then y will be 3 but not -1}
Therefore, P, Q, R are not collinear. (Answer)
Again if we consider the point S(-3,-1), it satisfies equation (1).{If you put x=-3 in the equation (1), y will be -1}.
Therefore, P, Q, and S lie on the same straight line. and they are collinear. (Answer)
