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3 years ago

Given m = (

Mathematics

1 answer:

DIA [1.3K]3 years ago

7 0

Answer:

i need to know the question to answer ir

Step-by-step explanation:

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Which division problem does the model below show? 4 fraction bars. The fraction bars are labeled 1 and each have 6 boxes underne

Ksivusya [100]

Answer:

4 divided by one-sixth = 2

Step-by-step explanation:

Given 4fraction bars

If each fraction bars has 6boxes, then we can get the total boxes for 4fractiom bars as shown;

1 fraction bars = 6boxes

4fraction bars = x

Cross multiply

1 × x = 4×6

x = 4× 6/1

x = 4 ÷ 1/6

Hence the division problem that modelled the expression is 4 ÷ 1/6

4÷1/6 = 4×6/1

4÷1/6 = 24

Option A is correct

4 0

3 years ago

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William is throwing a party for his math class and decides to visit Jones Pi Bakery. There, cupcakes cost $2 and Pies cost $7.50

raketka [301]

Answer: Just time 2 x 73 and you will get 146

Step-by-step explanation:

4 0

3 years ago

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1. This composite figure is created by placing a sector of a circle on a rectangle. What is the area of this composite figure? S

White raven [17]

Answer:

29.92 m² (nearest hundredth)

Step-by-step explanation:

$\textsf{Area of a sector}=\dfrac{\theta}{360\textdegree}\pi r^2$

$\implies \textsf{area}=\dfrac{30}{360\textdegree}\pi \cdot 5.5^2=\dfrac{121}{48}\pi \textsf{ m}^2$

Area of rectangle = width × length

⇒ area = 4 × 5.5 = 22 m²

Total area = area of sector + area of rectangle

⇒ total area = $\dfrac{121}{48}\pi +22$ = 29.91943148... = 29.92 m² (nearest hundredth)

6 0

2 years ago

The length of a rectangle is 4cm longer than the width, and the perimeter is at least 48cm. What are the smallest possible dimen

jenyasd209 [6]

So since the length is 4+w. Then the perimeter 2(4+w) + 2w >= 48.
so, 8+2w+2w>=48.
8+4w>=48
4w>=40
w>=10
so, the width must be at least 10. And the smallest dimensions can be 10 x 14.

3 0

3 years ago

At a rally attended by 520 people, 30% were fantes, 25% were ewes, 15% were nzemas, 20% were gas and the rest were gonjas. How m

mariarad [96]

Answer:

No. of gonjas = 52

No. of more nzemas than fantes = 78

Step-by-step explanation:

Total no. of people = 520

No. of fantes = $\frac{30}{100}$ × 520

No. of fantes = 156

No. of ewes = $\frac{25}{100}$ × 520 = 130

No. of nzemas = $\frac{15}{100}$ × 520 = 78

No. of gas = $\frac{20}{100}$ × 520 = 104

No. of gonjas = 520 - (156 + 130 + 78 + 104) = 52

No. of fantes = 156

No. of nzemas = 78

No. of more nzemas than fantes = 156 - 78 = 78

Pie chart of the following problem is shown below.

5 0

4 years ago

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