1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elixir [45]
3 years ago
8

Find the radius y of circle C, given that x = 12 and z = y + 8.

Mathematics
1 answer:
aivan3 [116]3 years ago
6 0

Answer:

y = 5

Step-by-step explanation:

use Pythagorean theorem

                 z² = x² + y²

         (y + 8)² = 12² + y²

y² + 16y + 64 = 144 + y²

               16y = 80

                   y = 5

You might be interested in
Use the diagram shown to help you find the m∠LNM.
attashe74 [19]

Answer:

135 is your answer......

7 0
2 years ago
Factorise completely
Andreyy89
1. Number that adds up to -12 and multiplied by the same # that gives u -13. Set it up like this because both are negative so, u need 1 negative and 1 positive.
(x-13)(x+1)

2. Same rule applies. GCF
8y(4y+1)

3. (x+3)(x-3)
4 0
3 years ago
During the first part of a​ trip, a canoeist travels 18 miles at a certain speed. the canoeist travels 4 miles on the second par
storchak [24]
We can set it up like this, where <em>s </em>is the speed of the canoeist:

\frac{18}{s} + \frac{4}{s-5} = 3

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):

s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s

If we rearrange this, we can turn it into a quadratic equation and factor:

18s - 90+4s=3 s^{2} -15s \\ 22s-90=3 s^{2} -15s \\ 3 s^{2} -37s+90=0 \\ (3s-10)(s-9)=0 \\ s= \frac{10}{3} ,9

Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater."  We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

9-5 = 4

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
5 0
3 years ago
SOMEONE PLEASE HELP ME ASAP PLEASEEE!!!​
JulsSmile [24]

Answer:

m-9

Step-by-step explanation:

12-9= 3

14-9= 5

18-9= 9

27-9= 18

4 0
3 years ago
Read 2 more answers
A short necklace has 32 gold beads and 8 black beads.
joja [24]

Answer:

12 black beads

Step-by-step explanation:

Given the ration of gold beads to black beads on the short necklace:

\frac{gold}{black}=\frac{32}{8}=\frac{4}{1}

Since the ratio of 4:1 has 5 total parts, you can take the total amount of beads in the long necklace and divide by 5:

60 ÷ 5 = 12

12 beads represents 1 part of the ratio, so that would be the number of black beads.  To check, multiply 12 by 4:  12 x 4 = 48, and set up a ratio:

48: 12 = 4: 1

3 0
3 years ago
Other questions:
  • You sell an automobile part for $9.98, which includes a $.40 sales tax. The article cost you $8.75.
    9·1 answer
  • Plz help me I’m confused on to how to do this problem
    14·2 answers
  • The sum of 2 consecutive odd integers is 52. If x represents the smaller integer, then the larger integer is
    15·2 answers
  • 3. Seiji and Gavin both worked hard over the summer. Together, they earned a total of $425. Gavin earned $25 more than Seiji. Ho
    13·1 answer
  • Harold has been hired as a salesman. He is paid a flat rate of $375 each week and earns an additional $14.25 commission for each
    5·1 answer
  • Which scenario is represented by this equation? 1200 =3×+120
    9·1 answer
  • The numbber 14 is less than the number of hours nathans volleyball team trains in a week which of the follwoing inequalities rep
    11·1 answer
  • 7th Grade Math<br> Please help<br> -7 = 1/3 a<br> Find the value of a
    7·1 answer
  • Three friends but one pack of 80 stickers. They divide it equaly and gave the rest to the teacher. how many stickers will each f
    14·1 answer
  • Please help me with this system of equations problem
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!