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2 years ago

Find the radius y of circle C, given that x = 12 and z = y + 8.

Mathematics

1 answer:

aivan3 [116]2 years ago

6 0

Answer:

y = 5

Step-by-step explanation:

use Pythagorean theorem

z² = x² + y²

(y + 8)² = 12² + y²

y² + 16y + 64 = 144 + y²

16y = 80

y = 5

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Solve the equation below for x. сх — 4 = 7

RoseWind [281]

Answer:

x = 11/c

Step-by-step explanation:

To solve this equation for x, we simply need to apply equation operations and isolate the x variable.

cx - 4 = 7

cx - 4 + 4 = 7 + 4

cx = 7 + 4

cx = 11

cx * (1/c) = 11 * (1/c)

x = 11 * (1/c)

x = 11/c

Cheers.

5 0

3 years ago

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Simplify. 4ab5c(3a4b2c3) a. 12a5b3c4 b. 12a5b7c4 c. 12a5b10c4 d. 12a4b10c3

Brilliant_brown [7]

4ab^5c (3a^4b^2c^3) = 12a^5b^7c^4...answer B

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3 years ago

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goldfiish [28.3K]

1485 this is wrong I think

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2 years ago

BRAINLIEST ANSWER!!!!!

Shkiper50 [21]

Hmm....
I know that the first answer is a coin, but I'm not too sure about the second one.

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2 years ago

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Is domain of f(x,y) = 1 + (4 -y^2)^1/2 open, closed or neither is it bounded or unbounded?

omeli [17]

Answer:

Closed and Bounded.

Step-by-step explanation:

Hi there!

1) Let's start by finding the values in which the function is defined. Remember that this can be rewritten:

$f(x,y) = 1 + (4 -y^2)^{\frac{1}{2}} \:id\:est\:f(x,y)=1+\sqrt{(4 -y^2)}$

Since every quadratic root are defined for values $\geq$ 0 then, this help us to understand that we need calculate what interval this Domain is:

$4-y^{2} \geq 0\\4-y^{2}-4\geq -4\\-y^{2}\geq-4 \\y^{2}\leq4\\-2\leq y\leq 2$

$D=[-2,2]$

2) Graphically speaking, the domain is closed. For the values -2 and 2 are included, and bounded.

Bounded functions have all of their points contained by some circle origin centered. Check it out below.

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3 years ago