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liubo4ka [24]
3 years ago
5

Harold and cindy both found the sum of two 4-digit numbers, but their results were not the same. if kent made an error of additi

on by one in the tens column and cindy's result was correct, what was the difference between the larger result and the smaller result?
Mathematics
2 answers:
Fiesta28 [93]3 years ago
7 0
<span>The difference between the larger result and the smaller result was 10.

Suppose the 4 digits numbers are abcd and pqrs

Here, 1st Number is = 1000*a + 100*b + 10*c + d
and 2nd</span> Number is = 1000*ap + 100*q + 10*r + s

Then, since Kent made an error if 1 in tens columns and Harold added it correct, so the difference will be of 10 points.
Anton [14]3 years ago
6 0

Answer: 10 is the answer yall haha

Step-by-step explanation:

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ivolga24 [154]

Answer:

y = 5

Step-by-step explanation:

That "+5" elevates the graph of this cosine function 5 units above the x axis, and thus the "midline" you wanted is  y = 5.

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3 years ago
Hank and Lynn are both paying off car loans . • Hank paid $ 2,000 up front when he bought his car , and he pays $ 200 each month
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3 years ago
Factorize<br> ху<br> + 3x +3y<br> + 18
noname [10]

Answer:

(x+6)(y+3)

Step-by-step explanation:

  1. xy + 3x + 6y + 18
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URGENT URGENT URGENT URGENT URGENT
fiasKO [112]

Answer:

x=7

Step-by-step explanation:

To set up for this answer, we need to set it up as an equation: 2x+12=5x-9.

get the xs on one side and the whole numbers on the other.

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4 0
3 years ago
Read 2 more answers
for the given license plate configuration, determine how many different plates are possinle if letters and digits (a) can ba rep
Inessa05 [86]

Answer:

a) 1,757,600 different plates possible.

b) 1,404,000 different plates possible.

Step-by-step explanation:

The permutations formula is important to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

(a) can be repeated:

There are 3 letters, each one with 26 possible outcomes.

2 digits, each with 10 possible outcomes

So

T = 26*26*26*10*10 = 1757600

1,757,600 different plates possible.

(b) cannot be repeated:

Here the permutations formula is used.

Three letters, from a set of 26.

Two digits, from a set of 10. So

T = P_{(26,3)}*P_{(10,2)} = \frac{26!}{(26-3)!}*\frac{10!}{(10-2)!} = 1404000

1,404,000 different plates possible.

4 0
3 years ago
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