Answer:
At most 29 boxes can be safely loaded onto the pallet.
Step-by-step explanation:
Given:
Weight of each box = 55 pound
Weight pallet can support 
1595 pounds.
We need to find the number of boxes .
Solution:
Let the number of boxes loaded safely onto the pallet be 'x'.
So we can say that;
Weight of each box Multiplied by number of boxes should be less than or equal to Weight pallet can support.
framing in equation form we get;
Dividing both side by 55 we get;
Hence At most 29 boxes can be safely loaded onto the pallet.
Answer:
40%
Step-by-step explanation:
ok so first find the og price:
100% - 20% = 80%
so 80% = 200
let the 100% be x:
x * 0.8 = 200
x= 250
100% = 250
(difference/ og price) * 100% = the percentage decrease/ increase
(250-150/250)* 100% = 40%
OR
((the final price/ og price) * 100%) - 100%
((150/250)*100%) - 100% = 40%
There was a 40% decrease from the og price to the final price of 150.
Answer:
(a)i. Area=72 square feet
ii. Perimeter =34 feet
(b) Baseboard - perimeter
Carpet - area
Step-by-step explanation:
The room is 9ft x 8ft, therefore it is rectangular shaped.
Length=9ft; Breadth=8ft
(a)i. Area of a Rectangle= Length X Breadth
Area of the room=8X9=72 square feet
ii. Perimeter of a Rectangle=2(Length+Breadth)
Perimeter of the room=2(8+9)=2 X 17 =34 feet
(b) A baseboard goes around the edge or boundary of the room, so it has to do with perimeter
A carpet covers the entire floor so it has to do with the area of the room.
Answer:
yp = -x/8
Step-by-step explanation:
Given the differential equation: y′′−8y′=7x+1,
The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)
First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;
y′′−8y′=0
The auxiliary equation will give us;
m²-8m = 0
m(m-8) = 0
m = 0 and m-8 = 0
m1 = 0 and m2 = 8
Since the value of the roots are real and different, the complementary solution (yc) will give us
yc = Ae^m1x + Be^m2x
yc = Ae^0+Be^8x
yc = A+Be^8x
To get yp we will differentiate yc twice and substitute the answers into the original DE
yp = Ax+B (using the method of undetermined coefficients
y'p = A
y"p = 0
Substituting the differentials into the general DE to get the constants we have;
0-8A = 7x+1
Comparing coefficients
-8A = 1
A = -1/8
B = 0
yp = -1/8x+0
yp = -x/8 (particular integral)
y = yc+yp
y = A+Be^8x-x/8
