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ICE Princess25 [194]
3 years ago
13

I need help please??

Mathematics
1 answer:
Svet_ta [14]3 years ago
5 0

i think you answer would be b "omg all the b's xD"  I MIGHT BE WRONG THO and if i am in suuuper sorry :/

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in a company 95% of the workers are women if 220 people work for the company who aren't women how many workers are there in all?
dybincka [34]
So 5% of workers are not women, and 220 workers are not women, so 220 is 5% of the total workers. 220 is 5% of 4400, so there are 4400 workers in all.
7 0
2 years ago
A college bookstore marks up the price that it pays the publisher for a book by 35 %. If the selling price of a book is $ 87.00
Dimas [21]

Answer:the amount that the bookstore pay the publisher for the book is $64.4

Step-by-step explanation:

Let x represent the amount that the bookstore pay the publisher for the book.

The college bookstore marks up the price that it pays the publisher for a book by 35%. This means that the value of the mark up would be

35/100 × x = 0.35 × x = 0.35x

Therefore, the amount that the bookstore is selling the book would be

x + 0.35x = 1.35x

If the selling price of a book is $ 87.00, then it means that

1.35x = 87

x = 87/1.35 = 64.4

7 0
3 years ago
Which expression has a value of 0?
oee [108]

My Question:

Is there any answer choices?

6 0
2 years ago
Which expression is equivalent to ºd ?<br> O ata<br> O o-a<br> og<br> 90<br> O
yaroslaw [1]

Answer:

As by the picture, qp is the correct answer.

Step-by-step explanation:

Both are multiplication and in multiplication you can swap the factors and get the same answer every time.

6 0
2 years ago
Read 2 more answers
Find the indefinite integral. (Use C for the constant of integration.)
mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

u=(x^3-x^2+x)

Then

du = (3x^2-2x+1) dx

which allows us to do convert the original integral into a much simpler one of easy solution:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx  = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C

Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

7 0
2 years ago
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