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-BARSIC- [3]
3 years ago
11

A rectangle measuring 8in. by 12in.

Mathematics
1 answer:
Serggg [28]3 years ago
6 0
Ok, the perimeter of the rectangle is 40 inches.
You might be interested in
A quadrilateral has vertices A, B, C, and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units
Kryger [21]

Answer:

The correct option is O B'

Step-by-step explanation:

We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.

Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.

In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.

Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).

I will attach a drawing with an example.

Finally, we only have to look at the vertices and its original distances to answer the question.

The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'

8 0
3 years ago
If arc XV = 68° and ∠YUV = 36°, what is the measure of arc VY? A) 120° B) 130° C) 140° D) 150°
dybincka [34]
The picture in the attached figure

we have
arc XV = 68°∠YUV = 36°
 we know that
The measure of the external angle is the semidifference of the arcs that it covers.
therefore
∠YUV =[arc VY-arc XV]/2

arc VY=[2*∠YUV]+arc XV----------> [2*36]+68---------> 140°

the answer is
the measure of arc VY is 140°

6 0
3 years ago
Yesterday 160 guest at a hotel called for room service, and 240 guest did not called for room service. What is the percentage of
Dmitry [639]
160/400
80/200
40/100
C
8 0
3 years ago
Example 2
PIT_PIT [208]

Answer: (a) 314.2cm², (b) 157.1cm², (c) 78.55cm² (e) 6.77

Step-by-step explanation: (a)  Area of the circle with radius of 10 cm = πr²

                                                                          = 3.142 × 10 × 10

                                                                          = 3.142 × 100

                                                                          = 314.2cm²

The formula                                                       = πr²

(b)  Area of the half of a circle known as semicircle

                                                                         = πr²/2

                                                                         = 3.142 ×10 × 10/2

                                                                         = 3.142 × 50

                                                                         = 157.1cm²

The formula                                                      = πr²/2

(c)  A quarter of a circle is called quadrant

                                                            = πr²/4

                                                            = 3.142 × 10 × 10/4

                                                            = 314.2/4

                                                            = 78.55cm²

The formula is written thus = πr²/4, which implies that the circle is divided into 4 unit

(d) The conjecture about how to determine the area of the sector is

Formula of a sector = ∅/360(πr²)

<u>Information</u>

The arc  cant be 60°, therefore information incomplete.

(e) Area of the sector with the angle AOB of 60° = 24.

To find the radius of the angle, make v the subject of the formula from the formula.

Sector area = πr²∅/360°

equate formula to 24.

Therefore πr²∅/360° = 24

Multiply through by360° to make it a linear expression

It now becomes πr²∅ =24× 360°

                                                     r² = 24  x 360/π × ∅°

                                                     r² = 24 × 360° /3.142 × 60°

                                                     r² = 3,640/188.52

                                                     r² = 45.8

To find r , we take the square root of both side by applying laws of indicies

                                    Therefore r = √45 .8

                                                      r = 6.77

(f)   General formula = ∅°/360° × (πr²)

angle substended at centre by the arc = x°

assuming the radius of the circle = ycm, Therefore,  area of the sector = { ∅°/360° × πy² }

                                                     

                                                   

8 0
3 years ago
Sophia is dilating a figure. One of her pre-image points with coordinates (-3, 5) has an image with coordinates (-9, 15). If one
Galina-37 [17]
The dilation factor Sophia is using appears to be
  (image coordinate)/(original coordinate) = -9/-3 = 15/5 = 3

Then the problem tells us
  (pre-image point)×3 = (3, 1)
so we conclude
  (pre-image point) = (3, 1)/3 = (1, 1/3)
8 0
3 years ago
Read 2 more answers
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