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hodyreva [135]
3 years ago
5

Q.1 Thee are five girls and three boys in a group. The teacher chose one person at random. How could the teacher make a random c

hoice?
Q.2 A random number generator generates a whole number in the range 1 to 100. What is the probability it is 40 or more if the number is greater than 25?
Mathematics
1 answer:
Hatshy [7]3 years ago
4 0

Answer:

Q1: She can write names of each Student on separate Papers and choose one Randomly, the Result may be 5:3 Girls to Boys

Q2: 75/100

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Hank draws a line with a zero slope through the points (-2,4) and (3.b).which value of b could represent hanks second point ?
Agata [3.3K]
B = 4



A line with a slope of zero is a perfectly horizontal line, which means the y value (the second value) stays the same for every single point on the line.

So, if y equals 4 in the first point, then y still equals 4 in the second point, which means b is equal to 4.
4 0
4 years ago
Read 2 more answers
GCF of 4x^2y^2, 3xy^4, and 2xy^2
allsm [11]
The greatest common factor would be xy^2 because these are the only factors that they all have in common. The second term only has 1 x, so only 1 x is part of the gcf.

The 1st and 3rd terms each have y^2 therefore making it part of the gcf as well.
5 0
3 years ago
A construction elevator can carry at most 2,320 pounds. If the elevator operator weighs 195 pounds and each palette of roofing m
zvonat [6]
The maximum number of palettes that the elevator can carry in one trip is 5.

425 times 5= 2,125+ 195= 2,320


Hope this helps!! :-)
6 0
3 years ago
find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
3 years ago
Write y=-3x^2+12x-21 in vertex form
riadik2000 [5.3K]
Complete the square: 
<span>y = 3x^2 - 12x + 4 </span>
<span>y = 3(x^2 - 4x) + 4 </span>
<span>y = 3(x^2 - 4x + 4 - 4) + 4 </span>
<span>y = 3(x^2 - 4x + 4) - 12 + 4 </span>
<span>y = 3(x - 2)^2 - 8</span>
5 0
3 years ago
Read 2 more answers
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